d = distance between the two point charges = 60 cm = 0.60 m
r = distance of the location of point "a" where the electric field is zero from charge 
between the two charges.
= magnitude of charge on one charge
= magnitude of charge on other charge
= 3
= Electric field by charge at point "a"
= Electric field by charge at point "a"
Electric field by charge at point "a" is given as
= k /r²
Electric field by charge at point "a" is given as
= k /(d-r)²
For the electric field to be zero at point "a"
=
k /(d-r)² = k /r²
/(d-r)² = 3 /r²
1/(0.60 - r)² = 3 /r²
r = 0.38 m
r = 38 cm
Answer:
When the heat is heated it will be melted of ice, why it still remain at a constant temperature of 0◦ C.
Explanation:
Solution
The heat given by the heater will be used in melting of the ice, therefore the temperature will remain the same at the degree of 0◦ C.
After the ice is fully melted, the temperature of water will begin to increase with time.
Note: kindly find an attached document of the solutions with diagrams as part of this explanation
Answer:
P1 = 0 gage
P2 = 87.9 lb/ft³
Explanation:
Given data
Airplane flying = 200 mph = 293.33 ft/s
altitude height = 5000-ft
air velocity relative to the airplane = 273 mph = 400.4 ft/s
Solution
we know density at height 5000-ft is 2.04 × 
slug/ft³
so here P1 + 
= P2 + 
and here
P1 = 0 gage
because P1 = atmospheric pressure
and so here put here value and we get
P1 + = P2 +
0 + 
solve it we get
P2 = 87.9 lb/ft³
Answer:
24300000K
Explanation:
Q=mc(change in temperature)
900X2.0=1800.0
1800.0X13500= 24300K
Answer:
nope , sometimes we joke about the differences between us . but we don't hate yall
