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Sonbull [250]
3 years ago
5

Can someone help me out plz

Mathematics
1 answer:
EleoNora [17]3 years ago
3 0

Answer:

The answer is 43.52 you're welcome

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Which represents the solution(s) of the system of equations, y + 4 = x2 and y-x=2? Determine the solution set by
Sergeu [11.5K]

Answer:

The points (-2, 0) and (3,5) are the ONLY solutions of the given sets of equations.

Step-by-step explanation:

Here, the given equations are: y + 4 = x^{2}  , y -x = 2

Now checking for the given points:

(a) (-2, 0)

Here, y + 4 = 0 + 4 = 4 =   (-2)^{2}  =  x^{2} \\y- x = 0 -(-2) = 2  = RHS

Hence,  (-2, 0) is the solution of the given equations.

b) Checking for (2,0), as (-2, 0) is a solution as shown above

Here, y + 4 = 0 + 4 = 4 =   (2)^{2}  =  x^{2} \\y- x = 0 +  (-2) = -2  \neq 2(RHS)

Hence,  (2, 0) is NOT the solution of the given equations.

c) Checking for (3,5), as (-2, 0) is a solution as shown above

Here, y + 4 = 5 + 4 = 9 =   (3)^{2}  =  x^{2} \\y- x = 5 -3 = 2 -  (RHS)

Hence,   (3,5), is the solution of the given equations.

Hence, the points (-2, 0) and (3,5) are the ONLY solutions of the given sets of equations.

5 0
3 years ago
You are w rapping the boxed DVD collection as a present. What is
zhenek [66]
You will need a 8 in
7 0
3 years ago
What is the best method to separate a mixture of staples and salt?
schepotkina [342]

Answer:

A filter.

Step-by-step explanation:

6 0
3 years ago
Need help ASAP NO LINKS
matrenka [14]

Answer:

9

Step-by-step explanation:

5(n-2)=35

5n-10=35

5n=35+10

5n=45

n=45/5

n=9

Please mark me as brainliest

6 0
2 years ago
Read 2 more answers
The sums that appear when two fair? four-sided dice? (tetrahedrons) with sides 1?, 2?, 3?, and 4 are tossed
Karolina [17]

Answer:

The possible sums are 2, 3, 4, 5, 6, 7 & 8 (but they're not all equally likely)

Step-by-step explanation:

For example, the only way to get a sum of 2 is to roll a 1 and then a 1

And the only way to get a sum of 8 is to roll a 4 and then a 4 (imagine you don't roll the two dice simultaneously; this will help you to see the "other possibilities" that aren't obvious at first)

The probability of rolling a sum of 2 = probability of rolling sum of 8 (1/16 probability for each)

If you roll a 1 then a 2, or a 2 then a 1, there are 2 ways to get a sum of 3

If you roll a 3 then a 1, a 2 then a 2, or a 1 then a 3, there are 3 ways to get a sum of 4

If you roll a 4 then a 1, a 3 then a 2, a 2 then a 3, or a 1 then a 4, there are 4 ways to get a sum of 5 (5 is the most likely sum)

If you roll a 4 then a 2, a 3 then a 3, or a 2 then a 4, there are 3 ways to get a sum of 6

If you roll a 4 then a 3, or a 3 then a 4, there are 2 ways to get a sum of 7

5 0
3 years ago
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