Answer:
the average induced emf in the second winding is
Explanation:
The magnetic field inside the first solenoid is given by,
Where is the permeability of the free space
N is the number of turns of solenoid per unit length
I is the current in the solenoid
A is the cross-sectional area of the wire
Replacing we have,
Thus average emf induced in the second windigs is,
Therefore the average induced emf in the second winding is
Answer:
0.823 Nm
Explanation:
current, i = 100 A
radius, r = 10 cm
Angle between the normal and the magnetic field, θ = 30°
Magnetic field, B = 0.524 T
Torque is defined as the
Torque = 0.823 Nm
Thus, the torque is 0.823 Nm.
Answer:
The flux is 682.6 Wb.
Explanation:
Given that,
Vector field
We need to calculate the flux
Using formula of flux
Put the value into the formula
Hence, The flux is 682.6 Wb.
Answer:
W = 7000 J
Explanation:
To solve this problem we use that the speed of the bicycle is constant, therefore its acceleration is zero
F -fr = 0
F = fr
where F is the force applied by the child
Work is defined by
W = F. x
W = F x cos θ
in this case the child's force is parallel to the movement, therefore the angle is zero and cos 0 = 1
let's calculate
W = 35 200
W = 7000 J