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Kobotan [32]
4 years ago
12

A round loop of wire carries a current of 100 A, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a mag

netic field of 0.524 T. 1) What is the torque on the loop? (Express your answer to two significant figures.)
Physics
1 answer:
Oliga [24]4 years ago
7 0

Answer:

0.823 Nm

Explanation:

current, i = 100 A

radius, r = 10 cm

Angle between the normal and the magnetic field, θ = 30°

Magnetic field, B = 0.524 T

Torque is defined as the

\tau = i \times A\ B\times sin\theta

\tau = 100 \times 3.14\times 0.1\times 0.1\ 0.524\times 0.5

Torque = 0.823 Nm

Thus, the torque is 0.823 Nm.

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