Question

A round loop of wire carries a current of 100 A, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a magnetic field of 0.524 T. 1) What is the torque on the loop? (Express your answer to two significant figures.)

Answer 1

Answer:

0.823 Nm

Explanation:

current, i = 100 A

radius, r = 10 cm

Angle between the normal and the magnetic field, θ = 30°

Magnetic field, B = 0.524 T

Torque is defined as the

$\tau = i \times A\ B\times sin\theta$

$\tau = 100 \times 3.14\times 0.1\times 0.1\ 0.524\times 0.5$

Torque = 0.823 Nm

Thus, the torque is 0.823 Nm.