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aleksandrvk [35]
3 years ago
8

ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -

5j ohms. Add
these complex numbers to find the total impedance in the circuit.
=j ohms
Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

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