All categories

3 years ago

What is the distance between two and thirty six?

Mathematics

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer:

-34

Step-by-step explanation:

You might be interested in

Which linear function represents the line given by the point-slope equation y + 7 = –y plus 7 equals negative StartFraction 2 Ov

Citrus2011 [14]

Answer:

Negative Start Fraction 2 Over 3 End Fraction x minus 11

$f(x)=-\frac{2}{3}x-11$

Step-by-step explanation:

we have

$y+7=-\frac{2}{3}(x+6)$

Convert to slope intercept form

$y=mx+b$

Solve for y

That means -----> Isolate the variable y

Distribute in the right side

$y+7=-\frac{2}{3}x-\frac{2}{3}(6)$

$y+7=-\frac{2}{3}x-4$

subtract 7 both sides

$y=-\frac{2}{3}x-4-7$

$y=-\frac{2}{3}x-11$

Convert to function notation

Let

f(x)=y

$f(x)=-\frac{2}{3}x-11$

therefore

The linear function is

Negative Start Fraction 2 Over 3 End Fraction x minus 11

8 0

3 years ago

Read 2 more answers

0.27 repeating as a fraction in simplest form

Gre4nikov [31]

0.27 repeating as a fraction in simplest form is 3/11

6 0

3 years ago

\lim _{x\to 0}\left(\frac{2x\ln \left(1+3x\right)+\sin \left(x\right)\tan \left(3x\right)-2x^3}{1-\cos \left(3x\right)}\right)

Vinvika [58]

$\displaystyle \lim_{x\to 0}\left(\frac{2x\ln \left(1+3x\right)+\sin \left(x\right)\tan \left(3x\right)-2x^3}{1-\cos \left(3x\right)}\right)$

Both the numerator and denominator approach 0, so this is a candidate for applying L'Hopital's rule. Doing so gives

$\displaystyle \lim_{x\to 0}\left(2\ln(1+3x)+\dfrac{6x}{1+3x}+\cos(x)\tan(3x)+3\sin(x)\sec^2(x)-6x^2}{3\sin(3x)}\right)$

This again gives an indeterminate form 0/0, but no need to use L'Hopital's rule again just yet. Split up the limit as

$\displaystyle \lim_{x\to0}\frac{2\ln(1+3x)}{3\sin(3x)} + \lim_{x\to0}\frac{6x}{3(1+3x)\sin(3x)} \\\\ + \lim_{x\to0}\frac{\cos(x)\tan(3x)}{3\sin(3x)} + \lim_{x\to0}\frac{3\sin(x)\sec^2(x)}{3\sin(3x)} \\\\ - \lim_{x\to0}\frac{6x^2}{3\sin(3x)}$

Now recall two well-known limits:

$\displaystyle \lim_{x\to0}\frac{\sin(ax)}{ax}=1\text{ if }a\neq0 \\\\ \lim_{x\to0}\frac{\ln(1+ax)}{ax}=1\text{ if }a\neq0$

Compute each remaining limit:

$\displaystyle \lim_{x\to0}\frac{2\ln(1+3x)}{3\sin(3x)} = \frac23 \times \lim_{x\to0}\frac{\ln(1+3x)}{3x} \times \lim_{x\to0}\frac{3x}{\sin(3x)} = \frac23$

$\displaystyle \lim_{x\to0}\frac{6x}{3(1+3x)\sin(3x)} = \frac23 \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}\frac{1}{1+3x} = \frac23$

$\displaystyle \lim_{x\to0}\frac{\cos(x)\tan(3x)}{3\sin(3x)} = \frac13 \times \lim_{x\to0}\frac{\cos(x)}{\cos(3x)} = \frac13$

$\displaystyle \lim_{x\to0}\frac{3\sin(x)\sec^2(x)}{3\sin(3x)} = \frac13 \times \lim_{x\to0}\frac{\sin(x)}x \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}\sec^2(x) = \frac13$

$\displaystyle \lim_{x\to0}\frac{6x^2}{3\sin(3x)} = \frac23 \times \lim_{x\to0}x \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}x = 0$

So, the original limit has a value of

2/3 + 2/3 + 1/3 + 1/3 - 0 = 2

6 0

3 years ago

Solve the system of equation with substitution.

kipiarov [429]

Answer:

fgg I have to go to sleep otp tonight and I really want to talk to you tttttt and I really want to talk to you about it when I get home I will send you a picture of the back of the house and the time is right now but I will be there in a few minutes and I will be there in a few minutes and I will

5 0

4 years ago

How many times greater is the value 0.55 than the value 0.0055?

enyata [817]

Answer:

100

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers