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kkurt [141]
3 years ago
8

Ten points per answer plz hurry this is a timed quiz

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

the solution is given by s=9 because it makes the value of 3s+12 equal to 21

Step-by-step explanation:

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If I’m not mistaken, 16
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I need help with this​
Natali [406]

Answer: 1,004.8 cubic meters (choice D)

Work Shown:

V = (1/3)*pi*r^2*h

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V = 1,004.8

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DiKsa [7]

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x + 7

Step-by-step explanation:

5 + (x + 2) = x + 7

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3 years ago
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The table below shows the number of hours some business people in two states spend in meetings each week: State A 21 23 24 22 24
Lera25 [3.4K]
State A:
21,22,22,23,23,23,24,24,25

minimum = 21
Q1 = 22
Q2(median) = 23
Q3 = 24
maximum = 25
IQR = Q3 - Q1 = 24 - 22 = 2

state B:
20,20,21,22,23,23,24,46,50
minimum = 20
Q1 = (20 + 21)/2 = 20.5
Q2(median) = 23
Q3 = (24 + 46)/2 = 35
maximum = 50
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I do not believe they are symmetrical....I think state B is skewed to the right
6 0
3 years ago
Let X represent the full height of a certain species of tree. Assume that X has a normal distribution with a mean of 137.1 ft an
Rama09 [41]

Answer:

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 137.1, \sigma = 3.2

A tree of this type grows in my backyard, and it stands 132.3 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.

This is the pvalue of Z when X = 132.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{132.3 - 137.1}{3.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.

My neighbor also has a tree of this type growing in her backyard, but hers stands 143.5 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.

This is 1 subtracted by the pvalue of Z when X = 143.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{143.5 - 137.1}{3.2}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.

7 0
3 years ago
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