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3 years ago

Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24kg)

Physics

1 answer:

yKpoI14uk [10]3 years ago

7 0

Answer:

F = 683.8 N

Explanation:

The gravitational force of attraction between the Earth and the student is given by Newton's Law of Gravitation as follows:

$F = \frac{Gm_{1}m_{2}}{r^2}$

where,

F = Force = ?

G = Universal gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

m₁ = mass of Earth = 5.98 x 10²⁴ kg

m₂ = mass of student = 70 kg

r = distance between Earth and student = 6.39 x 10⁶ m

Therefore,

$F = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^1)(5.98\ x\ 10^{24}\ kg)(70\ kg)}{(6.39\ x\ 10^6\ m)^2}\\$

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A hot-water stream at 80 ℃ enters a mixing chamber with a mass flow rate of 0.5 kg/s where it is mixed with a stream of cold wat

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Answer:

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4 years ago

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$180^{\circ}-61^{\circ}$

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In order to find the y-component of the resultant force, we have to resolve each force along the y-axis.

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$180^{\circ}+52.8^{\circ}$

Therefore its y-component is

$F_{2y}=(5.40)(sin (180^{\circ}+52.8^{\circ}))=-4.30 N$