Question

Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24kg)

Answer 1

Answer:

F = 683.8 N

Explanation:

The gravitational force of attraction between the Earth and the student is given by Newton's Law of Gravitation as follows:

$F = \frac{Gm_{1}m_{2}}{r^2}$

where,

F = Force = ?

G = Universal gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

m₁ = mass of Earth = 5.98 x 10²⁴ kg

m₂ = mass of student = 70 kg

r = distance between Earth and student = 6.39 x 10⁶ m

Therefore,

$F = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^1)(5.98\ x\ 10^{24}\ kg)(70\ kg)}{(6.39\ x\ 10^6\ m)^2}$

F = 683.8 N