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Ber [7]
3 years ago
12

A material has a low resistivity. Which statement is the best prediction about

Physics
1 answer:
Ksivusya [100]3 years ago
8 0

Answer:A

Explanation:I’m taking the test rn and I got it correct

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The behaviors that light exhibits are reflection, refraction, diffraction, polarization, and dispersion. Answer
Molodets [167]
I believe the correct answer is false. The behaviors that light exhibits are reflection, refraction, diffraction but not polarization, and dispersion. Light<span> behaves as a wave - it undergoes reflection, refraction, and diffraction just like any wave would. Hope this answers the question.</span>
5 0
4 years ago
What impulse will be given to an object if it experiences a force of 0.5 N for 30 seconds
morpeh [17]

Answer:

<h2>15 Ns</h2>

Explanation:

The impulse of an object can be found by using the formula

impulse = force × time

From the question we have

impulse = 0.5 × 30

We have the final answer as

<h3>15 Ns</h3>

Hope this helps you

4 0
3 years ago
An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
IgorLugansk [536]

Answer:

The de Broglie wavelength of electron βe = 2.443422 × 10⁻⁹ m

The de Broglie wavelength of proton βp = 5.70 × 10⁻¹¹ m

Explanation:

Thermal kinetic energy of electron or proton = KE

∴ KE = 3kbT/2

given that; kb = 1.38 x 10⁻²³ J/K , T = 1950 K

so we substitute

KE = ( 3 × 1.38 x 10⁻²³ × 1950 ) / 2

kE = 4.0365 × 10⁻²⁰ (  is the kinetic energy for both electron and proton at temperature T )

Now we know that

mass of electron M'e = 9.109 ×  10⁻³¹

mass of proton M'p = 1.6726 ×  10⁻²⁷

We also know that

KE = p₂ / 2m

from the equation, p = √ (2mKE)

{ p is momentum, m is mass }

de Broglie wavelength = β

so β = h / p = h / √ (2mKE)

h = Planck's constant = 6.626 ×  10⁻³⁴

∴ βe =  h / √ (2m'e × KE)

βe = 6.626 ×  10⁻³⁴ / √ (2 × 9.109 ×  10⁻³¹ × 4.0365 × 10⁻²⁰ )

βe = 6.626 ×  10⁻³⁴ / √  7.3536957 × 10⁻⁵⁰

βe = 6.626 × 10⁻³⁴  / 2.71176984642871 × 10⁻²⁵

βe = 2.443422 × 10⁻⁹ m

βp =  h / √ (2m'p ×KE)

βp = 6.626 ×  10⁻³⁴ / √ (2 × 1.6726 ×  10⁻²⁷ × 4.0365 × 10⁻²⁰ )

βp = 6.626 ×  10⁻³⁴ / √ 1.35028998 × 10⁻⁴⁶

βp =  6.626 ×  10⁻³⁴ / 1.16201978468527 ×  10⁻²³

βp = 5.702140 × 10⁻¹¹ m

3 0
3 years ago
A certain humidifier operates by raising water to the boiling point and then evaporating it. Every minute 30 g of water at 20◦ C
Sveta_85 [38]

Answer:

The value of total energy needed per minute for the humidifier = 77.78 KJ

Explanation:

Total energy per minute the humidifier required = Energy required to heat water to boiling point) + Energy required to convert liquid water into vapor at the boiling point) ----- (1)

Specific heat of water = 4190 \frac{J}{kg k}

The heat of vaporization is =  2256 \frac{KJ}{kg}

Mass = 0.030 kg

Energy needed to heat water to boiling point =  m c ( T_{2} - T_{1} )

Energy needed to heat water to boiling point = 0.030 × 4.19 × (100 - 20)

Energy (E_{1}) = 10.08 KJ

Energy needed to convert liquid water into vapor at the boiling point

E_{2} = 0.030 × 2256 = 67.68 KJ

Thus the total energy needed E =  E_{1} + E_{2}

E = 10.08 + 67.68

E = 77.78 KJ

This is the value of total energy needed per minute for the humidifier.

9 0
3 years ago
A point charge q1 = is located at the center of a thick conducting spherical shell of inner radius a = 2.2 cm and outer radius b
Yanka [14]

Answer:

Ex(P) = -3.602 x 10^6 N/C

Explanation:

  • given q1 = -5.7μC
  • q2 = 2.6 μC = the net charge on the conducting shell
  • inner radius of conducting shell = a = 2.2 cm =0.022m
  • outer radius of conducting shell = b = 4.5 cm = 0.045m

1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;

Ex(P) = k(q1+q2)/r^2

= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2

Ex(P) = -27.9 x 10^3/ 0.007744

Ex(P) = -3.602 x 10^6 N/C

7 0
4 years ago
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