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Lina20 [59]
3 years ago
14

A motorist travels a distance of 406 km during a 7 hr period. What was the average speed in (a) km/hr and (b) m/sec?

Physics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

The average speed was 58 \frac{km}{hr} or 16.11 \frac{m}{sec}

Explanation:

Speed ​​is a physical quantity that expresses the relationship between the space traveled by an object, the time used for it and its direction. Its unit of measurement in the International System (S.I.) is the meter per second \frac{m}{s}.

So:

speed=\frac{distance}{time}

In this case you know:

  • distante= 506 km
  • time=7 hr

Replacing:

speed=\frac{406 km}{7 hr}

Solving:

speed=58 \frac{km}{hr}

Taking into account that 1 km is 1000 m and 1 hour is 60 minutes, which in turn is 60 seconds, the unit conversion is performed:

speed= 58\frac{km}{hr} * 1 000\frac{m}{km} *\frac{1}{60} \frac{hr}{minutes} *\frac{1}{60} \frac{minute}{sec}

speed=16.11 \frac{m}{sec}

<u><em>The average speed was 58 </em></u>\frac{km}{hr}<u><em> or 16.11 </em></u>\frac{m}{sec}<u><em></em></u>

Sholpan [36]3 years ago
4 0
The motorist travels (a) 58 km/h and (b) ~16.1 m/sec
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Explanation:

Given data

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The ammonia molecule (NH3) has a dipole moment of 5.0×10?30C?m. Ammonia molecules in the gas phase are placed in a uniform elect
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Question (continuation)

(a) What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to E S from parallel to perpendicular?

(b) At what absolute temperature T is the average translational kinetic energy 3/2kT of a molecule equal to the change in potential energy calculated in part (a)?

Answer:

a. 9.0 * 10^-24 Joules

b. 0.44K

Explanation:

Given

Let p = dipole moment = 5.0 * 10^-30 Cm

Let E = Magnitude = 1.8 * 10^6 N/m

a.

The charge in electric potential = Final Charge - Initial Charge

Initial Charge = Potential Energy

Initial Energy = -pE cosФ where Ф = 0

So, initial Energy = - 5.0 * 10^-30 * 1.8 * 10^6

Initial Energy = -9 * 10^-24 Joules

Final Energy = 0

Charge = 0 - (-9.0 * 10^-24)

Charge = 9.0 * 10^-24 Joules

b.

Absolute Temperature

Change in Kinetic Energy = Change in Potential Energy = 9.0 * 10^-24

Change in Kinetic Energy = 3/2kT where k is Steven-Boltzmann constant = 1.38 * 10^-23

So,

9.0 * 10^-24 = 3/2 * 1.38 * 10^-23 * T

T = (9.0 * 10^-24 * 2)/(3 * 1.38 * 10^-23)

T = (18 * 10^-24)/(4.14 * 10^-23)

T = 0.44K

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Which factor affects the force of gravity between objects? Check all that apply. A.direction
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The gravitational force between two masses is given by the formula

F=G\dfrac{Mm}{r^2}

where G is the <em>gravitational constant, </em>M is the larger mass, m is the smaller mass, and r is the distance between the centers of the objects. The values we can change here to affect that gravitational force are the <em>mass </em>and the <em>distance</em>. Time and shape have no impact on this force.

3 0
3 years ago
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Zielflug [23.3K]

Answer:

B. -900 kg-m/s2

Explanation:

First of all, we need to calculate the acceleration of the hockey player, which is given by:

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Substituting into the formula, we find

a=\frac{12 m/s-18 m/s}{0.6 s}=-10 m/s^2

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where m=90 kg is the mass of the hockey player. Substituting into the formula, we find

F=(90 kg)(-10 m/s^2)=-900 N

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