gawaingnpang nkabuhayan, hamon at oportinidad
Answer:
Explanation:
If E₀ is the electric field outside the smaller sphere and r is the radius of larger sphere.
E₀ = kQ/r²
The radius of the larger sphere is 3r and the charge on both sphere is same then the electric field outside the larger sphere is given as
E = kQ/(3r)² = kQ/9r² = 1/9 (kQ/r²)= 1/9 x E₀
hence the correct option is e.
** Missing information: The vertical distance from surface of liquid to bottom of the object is sought in this question, with the condition that the object is at equilibrium **
Ans: The vertical distance = y = M/(ρA)
Explanation:Support the vertical distance = y
Object's density = M/(A*h) (since A*h = volume)
By applying the condition,
(M/(Ah))/ρ = y/h
M/(ρAh) = y/h
y = M/(ρA)
Answer:
Explanation:
Given
Displacement is 
of Amplitude
i.e. 
, where A is maximum amplitude
Potential Energy is given by
Total Energy of SHM is given by
Total Energy=kinetic Energy+Potential Energy
Potential Energy is 
th of Total Energy
Kinetic Energy is 
of Total Energy
(c)Kinetic Energy is 
If we assume that the acceleration is constant, we can use on the kinematic equations:
Vf = Vi + a*t = 15 + 3*4 = 27 m/s
