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3 years ago

When very electronegative atoms, like oxygen, bond to atoms with a lower

Physics

2 answers:

-Dominant- [34]3 years ago

4 0

Answer:

Explanation:

B the oxygen atom becomes strongly positive

and

C HE HYDROGEN ATOM BECOMES PARTIALLY POSITIVE

PLS MARK MY ANSWER AS THE BRANLIEST

vladimir2022 [97]3 years ago

3 0

Answer:

The oxygen atom becomes strongly negative.

Explanation:

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When you ride a bike and make a turn, you can feel your body trying to move in the same direction the bike was going. Which of N

Alisiya [41]

Answer:

Explanation:

Newtons second law explains this the most because for every action their is an equal and opposite reaction. The reaction of you turning, causes the reaction of your whole body to turn with the bike.

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3 years ago

A repelling force occurs between two charged objects when

fgiga [73]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It would be 'when they have like charges.'

'Like charges' means the same charge. For example, two positive charged objects have like charges.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

2 years ago

a race car driver achieved a speed of 53m/s in 14 seconds after taking off from rest from the starting line. what was the averag

Veronika [31]

Answer:

53/14

Explanation:

average acceleration = (Vfinal -Vintial)/ time taken

3 0

2 years ago

Read 2 more answers

THE ANSWER!!! Please

Anuta_ua [19.1K]

Answer:

I think -7 N. Netforce is 3N-10N= -7N

Explanation:

5 0

2 years ago

A 2.4 kg block is dropped onto a spring and platform of negligible mass. The block is released

statuscvo [17]

The speed of the block when the compression is 15 cm is 9.85 m/s.

The given parameters;

<em>mass of the block, m = 2.4 kg</em>
<em>height of the block, h = 5 m</em>
<em>compression of the spring, x = 25 cm = 0.25 m</em>

The spring constant is calculated as follows;

$F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{2.4 \times 9.8}{0.25} \\\\k = 94.08 \ N/m$

The speed of the block when the compression is 15 cm can be determined by applying the principle of conservation of energy;

$\Delta K.E = \Delta P.E\\\\\frac{1}{2} m(v^2 - v_{0 }^2 ) = mgh - \frac{1}{2} kx^2\\\\\frac{1}{2} mv^2 = mgh - \frac{1}{2} kx^2\\\\mv^2 = 2mgh - kx^2\\\\v^2 = \frac{2mgh - kx^2}{m} \\\\v = \sqrt{\frac{2mgh - kx^2}{m}} \\\\v = \sqrt{\frac{(2 \times 2.4 \times 9.8 \times 5) - (94.08 \times 0.15^2)}{2.4}} \\\\v = 9.85 \ m/s$

Thus, the speed of the block when the compression is 15 cm is 9.85 m/s.

Learn more here:brainly.com/question/14289286

8 0

2 years ago