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Tasya [4]
3 years ago
9

When very electronegative atoms, like oxygen, bond to atoms with a lower

Physics
2 answers:
-Dominant- [34]3 years ago
4 0

Answer:

Explanation:

B the oxygen atom becomes strongly positive

and

C HE HYDROGEN ATOM BECOMES PARTIALLY POSITIVE

PLS MARK MY ANSWER AS THE BRANLIEST

vladimir2022 [97]3 years ago
3 0

Answer:

The oxygen atom becomes strongly negative.

Explanation:

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A skateboarder initially has 5 kJ of kinetic energy. As she freewheels along a flat section of path, she does 400 J of work agai
sweet [91]

The final kinetic energy of the skateboarder after she freewheels and did work against friction on the flat section of the path is 4,600 J.

<h3>Conservation of energy</h3>

The final kinetic energy of the stakeboarder is determined by applying the principle of conservation of energy as shown below;

ΔK.E = -W

K.Ef - K.Ei = -W

where;

  • K.Ef is the final kinetic energy
  • K.Ei is the initial kinetic energy
  • W is work done

K.Ef = K.Ei - W

K.Ef = 5,000 J - 400 J

K.Ef = 4,600 J

Thus, the final kinetic energy of the skateboarder is 4,600 J.

Learn more about kinetic energy here: brainly.com/question/25959744

4 0
2 years ago
What is water vapour coming from the soil called
Scrat [10]
Water vapor coming from  the soil is called transpiration. That is the process in which a planet releases water vapor from its leaves. Hoped that helped!!
3 0
3 years ago
A student in gym class swings from a rope and they are moving 5 m/s at the bottom of their swing. What is the height they reach
vaieri [72.5K]

Answer:

A

Explanation:

4 0
3 years ago
If the velocity of blood flow in the aorta is normally about 0.32 m/s, what beat frequency would you expect if 4.40-MHz ultrasou
dusya [7]

Answer:

The beat frequency is 0.0019 MHz.

Explanation:

Given that,

Velocity = 0.32 m/s

Frequency = 4.40 MHz

Speed of wave = 1540 m/s

We need to calculate the frequency

Case (I),

Observer is moving away from the source

Using Doppler's effect

f'=\dfrac{v-v'}{v}f

Where, v' = speed of observer

Put the value into the formula

f'=\dfrac{1540-0.32}{1540}\times4.40

f'=4.399\ MHz

Case (II),

Cell is as the source of sound of frequency f' and it moving away from the observer.

Using formula of frequency

f''=\dfrac{v-v_{s}}{v+v_{s}}\times f

f''=\dfrac{1540-0.32}{1540+0.32}\times4.399

f''=4.3971\ MHz

We need to calculate the beat frequency

\Delta f= f'-f''

\Delta f=4.399-4.3971=0.0019\ MHz

Hence, The beat frequency is 0.0019 MHz.

4 0
3 years ago
An electric field around two charged objects is shown.
mamaluj [8]

Answer: D

<u></u>

X: positive

Y: negative

Explanation:

It's either A or D and I chose A and got it wrong.

3 0
3 years ago
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