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lana [24]
3 years ago
6

Suppose a pendulum clock has been calibrated to be accurate in San Francisco, where g = 9.800 m/s2 . In Camrose, g = 9.811 m/s2

is slightly larger due to the effect of Earth’s rotation at a higher latitude. Explain why the clock will either run perfectly, run too quickly, or run too slowly in Camrose.
Physics
1 answer:
tamaranim1 [39]3 years ago
8 0

The clock would run too slowly in Camrose.

Since the period of the pendulum T = 2π√(L/g) where L = length of clock and g = acceleration due to gravity.

Now since g = 9.800 m/s² in San Francisco and g = 9.811 m/s² in Camrose, we see that g increases.

From the expression for the period T, since L is constant, we find that

T ∝ 1/√g

Since g increases, so, T would decrease.

Thus, the clock would run too slowly in Camrose.

Learn more about pendulum clock here:

brainly.com/question/12405819

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3 years ago
Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
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Answer:

Explanation:

See the attachment for the details.  A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times.  The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.  

The individual driving times and distances are summed to provide:

(<u>a) How far did he travel?</u>

103 km

<u>(b) What was his average speed?</u>

12.88 km/h

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8 0
3 years ago
According to Bernoulli's equation, the pressure in a fluid will tend to decrease if its velocity increases. Assuming that a wind
Pie

Answer:

The pressure drop predicted by Bernoulli's equation for a wind speed of 5 m/s

= 16.125 Pa

Explanation:

The Bernoulli's equation is essentially a law of conservation of energy.

It describes the change in pressure in relation to the changes in kinetic (velocity changes) and potential (elevation changes) energies.

For this question, we assume that the elevation changes are negligible; so, the Bernoulli's equation is reduced to a pressure change term and a change in kinetic energy term.

We also assume that the initial velocity of wind is 0 m/s.

This calculation is presented in the attached images to this solution.

Using the initial conditions of 0.645 Pa pressure drop and a wind speed of 1 m/s, we first calculate the density of our fluid; air.

The density is obtained to be 1.29 kg/m³.

Then, the second part of the question requires us to calculate the pressure drop for a wind speed of 5 m/s.

We then use the same formula, plugging in all the parameters, to calculate the pressure drop to be 16.125 Pa.

Hope this Helps!!!

7 0
3 years ago
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