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3 years ago

A piano with a mass of 130 kg is lifted 10m above the ground in 5 s by a crane.

Physics

2 answers:

hammer [34]3 years ago

7 0

The 2548 watts should be the power that is used by the crane according to the formula

Sergio [31]3 years ago

6 0

<em> $power = 2548 \: watt \\ solution \\ mass = 130 \: kg \\ distance = 10m \\ time = 5 \: sec \\ power = \frac{w}{t} \\ \: \: \: \: \: \: \: \: \: \: = \frac{f \times d}{t} \\ \: \: \: \: \: \: \: \: = \: \frac{m \times g \times d}{t} \\ \: \: \: \: \: \: \: \: \: = \frac{130 \times 9.8 \times 10}{5} \\ \: \: \: \: \: \: \: \: = \frac{12740}{5} \\ \: \: \: \: \: = 2548 \: watt \\ hope \: it \: helps$ </em>

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Assume you need to design a hydronic system that can deliver 80,000 Btu/hr. What flow rate of water is required if the temperatu

PolarNik [594]

Answer:

At 10°F change in temperature

Mass flowrate = 1.01 kg/s = 2.227 lbm/s

Volumetric flowrate = 1010 m³/s = 35667.8 ft³/s

At 20°F change in temperature

Mass flowrate = 0.505 kg/s = 1.113 lbm/s

Volumetric flowrate = 505 m³/s = 17833.9 ft³/s

Explanation:

80000 btu/hr = 23445.7 W

P = ṁc(ΔT)

ṁ = MASS flowrate

c = specific heat capacity of water = 4182 J/kg.K,

ΔT = change in temperature = 10°F

To convert, a change of 18°F is equal to a change of 10°C

A change of 10°F = 10×10/18 = 5.556°C = 5.556K

P = ṁc(ΔT)

23445.7 = ṁ(4182 × 5.556)

ṁ = 23445.7/(4182 × 5.556)

ṁ = 1.01 kg/s = 2.227 lbm/s

In volumetric flow rate, Q = density × mass flowrate = 1000 × 1.01 = 1010 m³/s = 35667.8 ft³/s

For a change of 20°F,

ΔT = change in temperature = 20°F

To convert, a change of 18°F is equal to a change of 10°C

A change of 20°F = 20×10/18 = 11.1111°C = 11.111K

P = ṁc(ΔT)

23445.7 = ṁ(4182 × 11.111)

ṁ = 23445.7/(4182 × 11.111)

ṁ = 0.505 kg/s = 1.113 lbm/s

In volumetric flow rate, Q = density × mass flowrate = 1000 × 0.505 = 505 m³/s = 17833.9 ft³/s

Hope this Helps!!!

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3 years ago

A karate master strikes a board with an initial velocity of 10.0 m/s, decreasing to 1.0 m/s as his hand passes through the board

kenny6666 [7]

The force exerted on the board by the karate master given the data is -4500 N

<h3>Data obtained from the question </h3>

Initial velocity (u) = 10 m/s
Final velocity (v) = 1 m/s
Time (t) = 0.002 s
Mass (m) = 1 Kg
Force (F) = ?

<h3>How to determine the force</h3>

The force exerted can be obtained as illustrated below:

F = m(v - u) / t

F = 1 (1 - 10) / 0.002

F = (1 × -9) / 0.002

F = -4500 N

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brainly.com/question/250648

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