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MAVERICK [17]
3 years ago
12

At the beginning of year 1, Lisa invests $500 at an annual compound interest

Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Answer:

the actual answer is a(n)= 500 * ( 1 + 0.03) ^(n - 1) ;$579.64

Step-by-step explanation:

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What is the maximum percent of net spendable income that should be set aside for housing
stepladder [879]

Answer:

Answer;


-38 %

Step-by-step explanation:

Explanation;


-Budget busters are the large potential problem areas that can destroy a budget. Failure to control even one of these problem areas can result in financial disaster.


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-Food takes 12 percent of your monthly budget.  The reduction of a family's food bill requires quantity and quality planning.


-Transportation (purchase and maintenance), takes 15 percent of your monthly budget, Debts takes 5 percent of Net Spendable Income, Insurance takes 5 percent of Net Spendable Income assuming an employer provides medical insurance, Recreation/Entertainment takes 5 percent of Net Spendable Income, Clothing takes 5 percent of Net Spendable Income, Medical and dental takes 5 percent of Net Spendable Income and Savings takes 5 percent of Net Spendable Income

7 0
3 years ago
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Will mark brainliest. will be reported if only for the points
tia_tia [17]

Answer:

d=~7.6

Step-by-step explanation:

7^2+3^2=d^2

49+9=d^2

58=d^2

Square root of 58=~7.6

d=~7.6

6 0
3 years ago
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Jeff has two sticker-printing machines. Each machine can print 42 stickers per minute. On day 1, only the first machine was used
tankabanditka [31]
All you have to do is x times 42 plus y times 42 and then you have to add the first day on which is 89.This is how it should look (x*42)+(y*42)+89.
3 0
3 years ago
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
What is the Slope and y intercept
Inessa [10]

Answer:

The slope is .075 and the y intercept is -.125

Step-by-step explanation:

8y = .2(3x -5)

Distribute the .2

8y = .6x - 1

Divide by 8

8y/8 = .6x/8 -1/8

y = .075x -.125

This is in slope intercept form  y= mx+b  where m is the slope and b is the y intercept.

The slope is .075 and the y intercept is -.125

5 0
3 years ago
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