About 3 gallons of blue paint will be needed because if you add 175+175 it equals 350 and then add another 175 it equals 525.
We have been given that ∠Q is an acute angle such that 
. We are asked to find the measure of angle Q to nearest tenth of a degree.
We will use arctan to solve for measure of angle Q as:
Now we will use calculator to solve for Q as:
Upon rounding to nearest tenth of degree, we will get:
Therefore, measure of angle Q is approximately 2.3 degrees.
<h2><em>To enlarge or reduce any shape you must begin by working out the scale factor, this is calculated by using the following formula:
</em></h2><h2><em>
</em></h2><h2><em>For an enlargement = large number ÷ small number
</em></h2><h2><em>
</em></h2><h2><em>For a reduction = small number ÷ large number</em></h2>
You didn’t add a picture !
Answer:
D. F(x) = 2(x-3)^2 + 3
Step-by-step explanation:
We are told that the graph of G(x) = x^2, which is a parabola centered at (0, 0)
We are also told that the graph of the function F(x) resembles the graph of the function G(x) but has been shifted and stretched.
The graph of F(x) shown is facing up, so we know that it is multiplied by a <em>positive</em> number. This means we can eliminate A and C because they are both multiplied by -2.
Our two equations left are:
B. F(x) = 2(x+3)^2 + 3
D. F(x) = 2(x-3)^2 + 3
Well, we can see that the base of our parabola is (3, 3), so let's plug in the x value, 3, and see which equation gives us a y-value of 3.
y = 2(3+3)^2 + 3 =
2(6)^2 + 3 =
2·36 + 3 =
72 + 3 =
75
That one didn't give us a y value of 3.
y = 2(3-3)^2 + 3 =
2(0)^2 + 3 =
2·0 + 3 =
0 + 3 =
3
This equation gives us an x-value of 3 and a y-value of 3, which is what we wanted, so our answer is:
D. F(x) = 2(x-3)^2 + 3
Hopefully this helps you to understand parabolas better.
