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3 years ago

What holds the earth in place

Chemistry

2 answers:

anastassius [24]3 years ago

5 0

Gravity? Sorry if im wrong im just guessing

amm18123 years ago

5 0

The Earth is not held in place, but rather in a constant orbit around the sun. However, this could be reffered to as "in place" since the Earth has not moved outside this orbit since the birth of the universe. So, you ask what keeps the Earth in a constant, nonfluctuating orbit? The pull of gravity coming from the sun and the other planets.

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An architect wants to design a solar house in the northern hemisphere. For maximum, which side of the house should have the most

Natalija [7]

Hello!! My answer would be that they should add the solar panels that faces the south. Since the sun rises in the east and sets in the west, the south portion would get both sunlight from the east and west sides. I hope this helps!!

3 0

3 years ago

Read 2 more answers

Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.

weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0

3 years ago

I am so lost, and suggestions to how I can solve this?

Ad libitum [116K]

<h3>Answer:</h3>

165.078 g

<h3>Explanation:</h3>

<u>We are given;</u>

Specific heat capacity of nickel as 0.446 J/g°C
Initial temperature of nickel is 255.5 °C
Mass of water in the calorimeter is 250.0 g
Initial temperature of water is 20° C
Final temperature of the mixture is 35.5°C

Specific heat capacity of water is 4.18 J/g°C

We are required to calculate the mass of nickel sample;

<h3>Step 1: Calculate the amount of heat absorbed by water.</h3>

We know that quantity of heat absorbed, Q = m × c × ΔT

Change in temperature, ΔT = 35.5°C - 20°C

= 15.5 °C

Therefore, Q = 250 g × 4.1 J/g°C × 15.5° C

= 16,197.5 Joules

<h3>Step 2: Calculate the amount of heat released by nickel sample</h3>

Assuming the mass of nickel sample is m

Then, Heat released, Q = m × c × ΔT

Change in temperature, ΔT = 255.5 °C - 35.5 ° C

= 220 °C

Q = m × 0.446 J/g°C × 220° C

= 98.12m joules

<h3>Step 3: Determine the mass of nickel sample</h3>

We know that the amount of heat absorbed is equivalent to amount of heat released.

That is, Quantity of heat absorbed = Quantity of heat released

Therefore;

98.12 m joules = 16,197.5 Joules

m = 165.078 g

Thus, the mass of nickel sample is 165.078 g

8 0

4 years ago

If 6.00 g of the unknown compound contained 0.200 mol of C and 0.400 mol of H, how many moles of oxygen, O, were in the sample?

Arada [10]

Convert moles to mass.

mass C = 0.2 mol * 12 g / mol = 2.4 g

mass H = 0.4 mol * 1 g / mol = 0.4 g

So mass left for O = 6 g – (2.4 g + 0.4 g) = 3.2 g

Calculating for moles O given mass:

moles O = 3.2 g / (16 g / mol) = 0.2 moles

Answer:

<span>0.2 moles O</span>

8 0

4 years ago

Read 2 more answers

The density of a block of wood with a volume of 50 cubic centimeters and a mass of 100 grams is?

german

2 g/cm³ is the density of the block of wood

Explanation:

To determine density of the block of wood we use the following formula:

density = mass / volume

density of the wood block = 100 g / 50 cm³

density of the wood block = 2 g/cm³

Learn more about:

density

brainly.com/question/13295193

#learnwithBrainly

7 0

3 years ago