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allsm [11]
3 years ago
14

Your family is going to drive to your grandma's house for Christmas dinner. You set the car's odometer to 0 before you leave. Wh

en you arrive, the odometer reads 42.6 miles. Looking at a map, you see the direct, straight-line distance is 30 miles due east. When you return home, what will be your distance and displacement for the round trip, in that order?
Physics
1 answer:
Sati [7]3 years ago
4 0

Answer:

Distance = 85.3 miles

displacement = 0

Explanation:

The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;

Total distance for the round trip = 42.6 + 42.6 = 85.2 miles

Since the trip was a round trip, the displacement is zero because the family returned to their initial location.

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What happens to the current in a circuit when the resistance is increased
VikaD [51]

then the current will decrease.

hope this helps :)

5 0
3 years ago
At an equilibrium position of a pendulum, the <br> is at a maximum.
Stolb23 [73]

Answer:

velocity

Explanation:

edge 2021

7 0
3 years ago
The displacement in simple harmonic motion is a maximum when the 1. velocity is a maximum. 2. kinetic energy is a maximum. 3. ve
dlinn [17]

Answer:

3. velocity is zero.

Explanation:

The velocity of a simple harmonic motion is given by

v = \omega\sqrt{A^2-x^2}

Here, <em>ω</em> is the angular velocity, <em>A</em> is the amplitude (or maximum displacement from the equilibrium point) and <em>x</em> is the displacement at any time.

At maximum displacement, <em>x </em>=<em> A</em>.<em> </em>Then

v = \omega\sqrt{A^2-A^2} = 0

Therefore, at maximum displacement, velocity is 0.

Practically, this can be observed in a simple pendulum. As it approaches the maximum displacement, its velocity reduces. It becomes zero at this point and then reverses as the pendulum changes course. Then the velocity begins to increase. It becomes maximum at the equilibrium point but once past that, the velocity begins to reduce as it approaches the other amplitude.

For acceleration,

a = -\omega^2x

It follows that at maximum displacement, the acceleration is a maximum. The negative sign indicates that it is in an opposite direction to the displacement. Both kinetic energy (\frac{1}{2}mv^2) and linear momentum (mv) are proportional to velocity; they are therefore both zero at the maximum displacement.

5 0
3 years ago
If a train is going 60 m/s hits the brakes, and it takes the train 1 minute 25 seconds to stop, what is the train’s acceleration
Cloud [144]
Hey there, the answer is ..............................  About 0.7 m/sec^2
<span>
Acceleration is the change in speed / time </span>

<span>Change in speed is 60 m/sec </span>

<span>Time is 1 minute 25 second. Convert that to seconds. </span>

<span>Divide the change in speed by the time in seconds.

About 0.7 m/sec^2

 </span><span>So the acceleration is - 60 / 85 = - 0.71 m/s^2 

HOPE I HELPED!!!!!!!!!!
</span>
8 0
3 years ago
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011
nlexa [21]

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
2 years ago
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