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allsm [11]
3 years ago
14

Your family is going to drive to your grandma's house for Christmas dinner. You set the car's odometer to 0 before you leave. Wh

en you arrive, the odometer reads 42.6 miles. Looking at a map, you see the direct, straight-line distance is 30 miles due east. When you return home, what will be your distance and displacement for the round trip, in that order?
Physics
1 answer:
Sati [7]3 years ago
4 0

Answer:

Distance = 85.3 miles

displacement = 0

Explanation:

The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;

Total distance for the round trip = 42.6 + 42.6 = 85.2 miles

Since the trip was a round trip, the displacement is zero because the family returned to their initial location.

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mixas84 [53]
Does it have to be that exact word. cause it is just another term for psuedopodium

5 0
3 years ago
When a nerve cell depolarizes, charge is transferred across the cell membrane, changing the potential difference. For a typical
laila [671]

Answer:

I = 18 x 10⁻⁹ A = 18 nA

Explanation:

The current is defined as the flow of charge per unit time. Therefore,

I = q/t

where,

I = Average Current passing through nerve cell

q = Total flow of charges through nerve cell

t = time period of flow of charges

Here, in our case:

I = ?

q = (9 pC)(1 x 10⁻¹² C/1 pC) = 9 x 10⁻¹² C

t = (0.5 ms)(1 x 10⁻³ s/1 ms) = 5 x 10⁻⁴ s

Therefore,

I = (9 x 10⁻¹² C)/(5 x 10⁻⁴ s)

<u>I = 18 x 10⁻⁹ A = 18 nA</u>

6 0
3 years ago
Ben rushin is waiting at a stoplight. when it finally turns green, ben accelerated from rest at a rate of a 6.00 m/s2 for a time
jasenka [17]

In the 4.10 seconds that elapsed, Ben reaches a velocity of

v_f=v_0+at\implies v_f=0\,\dfrac{\mathrm m}{\mathrm s}+\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)(4.10\,\mathrm s)

\implies v_f=24.6\,\dfrac{\mathrm m}{\mathrm s}

In this time, his displacement \Delta x satisfies

{v_f}^2-{v_0}^2=2a\Delta x\implies\left(24.6\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)\Delta x

\implies\Delta x=50.4\,\mathrm m

4 0
3 years ago
A 14 kg tennis ball moves at a velocity of 11 m/s. The ball is struck by a racket, causing it to rebound in the opposite directi
Charra [1.4K]

To solve this problem we will apply the concepts related to the momentum.

This is defined as the product between the change in velocity and the mass of the object, that is

p = m\Delta v

p = m (v_f-v_i)

Where,

m = mass

v_f = Final velocity

v_i = Initial velocity

Our values are given as,

m = 14kg

v_i= 11m/s

v_f= - 5m/s \rightarrow <em>the negative Symbol implies that the direction is opposite to the initial one and therefore there is also a change in the sense of magnitude</em>

p = (14)(-5-11)

p = 14(-16)

p = -224 kg \cdot m/s

The negative symbol indicates that the momentum has a direction opposite to that of the initial velocity. Or failing that, it has the same direction of the final speed

7 0
3 years ago
The width of the central maximum is defined as the distance between the two minima closest to the center of the diffraction patt
Gnom [1K]

Answer:

The value of the angle is \bf{ \sin^{-1}[h/am_{e}v]}.

Explanation:

Given:

The condition for diffraction minima is

a \sin \theta = m \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

where, a is the slit-width, \theta is the angle of incidence, m is the order number and \lambda is the wavelength of the light.

The wavelength of an electron traveling through a medium is governed by de Broglie's hypothesis.

According to de Broglie's hypothesis

\lambda &=& \dfrac{h}{p}\\               &=& \dfrac{h}{m_{e}v}

Here, h is Planck's constant, m_{e} is the mass of the electron and v is the velocity of the electron.

For first minimum m = 1.

From equation (1), we have

&& a \sin \theta = \dfrac{h}{m_{e}v}\\&or,& \theta = \sin^{-1}[\dfrac{h}{am_{e}v}]

6 0
3 years ago
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