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1 answer:
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a) c = 1.85
b) c = 0.8
c) c = 2.33
Explanation:
a)
The displacement of the particle is given by
While the force applied on the particle is
So we have a problem in 2-dimensions.
The work done on the particle is given by the scalar product between force and displacement:
(1)
Here the work done on the particle is zero, so
W = 0
Therefore from eq(1) we find:
b)
In this problem, the work done on the particle is
The force and displacement are still
(displacement)
(force)
Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:
c)
In this problem instead, the work done on the particle is negative:
As before, the force and displacement are
(displacement)
(force)
And so again, we calculate the scalar product between force and displacement and we equate it to the work done on the particle, -1.8 J.
Doing so, we find:
Answer:
The work done on the gas is equal to the area under the curve pv diagram w = area of triangle = 1/2 (base)(height) = 1/2 (BC)(Ac) = 1/2 (3v - v)(3p - p) = 1/2 (9 vp - 3 vp - 3vp + vp) = 4 vp/2 W = 2 vp
Check attachment for the diagrammatic representation
