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3 years ago

Three functions of the stem

2 answers:

7 0

1.Stems support the plant body

2. Stems transport materials between the root system, the leaves and the reproductive structures

3.Stems hold up reproductive structures, like flowers, which helps pollinators, such as bees, find the flowers.

Mandarinka [93]3 years ago

6 0

<u>The three functions of the stem:</u>

To support the leaves,
To conduct water, and
To conduct minerals to the leaves.

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Help please Thank You so much!

Irina18 [472]

If you count the number of electrons (small dots), you have the atomic number. In this case you have 11 so this atom is a sodium atom. Sodium has 1 valence electron (electron on the outer shell) and chlorine has 7. This means that if sodium gave one electron away and chlorine would obtain one electron, they would both have the (ideal) noble gas conformation (full outer shell).

4 0

3 years ago

Matthew added a sample of sodium chloride to water and

viktelen [127]

Answer:

11.45

Explanation:

The ph is just 14-pOH so

14-2.55=ph=11.45

3 0

2 years ago

you are exploring the properties of a piece of matter you cut it in half several times which property of matter changes

Lapatulllka [165]

Only Extensive properties of piece will be changed. i.e Mass, Volume, Length etc.

3 0

3 years ago

Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow

andreyandreev [35.5K]

Explanation:

(a) The given data is as follows.

Pressure on top ( $P_{o}$ ) = 140 bar = $1.4 \times 10^{7} Pa$ (as 1 bar = $10^{5}$ )

Temperature = $15^{o}C$ = (15 + 273) K = 288 K

Density of gas = $\frac{PM}{ZRT}$

$\frac{dP}{dZ} = \rho \times g$

$\frac{dP}{dZ} = \int \frac{PM}{ZRT}$

$\int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ$

$ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}$

= 0.4548

$P_{1} = P_{o} \times e^{0.4548}$

= $1.4 \times 10^{7} Pa \times 1.5797$

= $2.206 \times 10^{7} Pa$

Hence, pressure at the natural gas-oil interface is $2.206 \times 10^{7} Pa$ .

(b) At the bottom of the tank,

$P_{2} = P_{1} + \rho \times g \times h$

= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

= $309.8 \times 10^{5} Pa$

= 309.8 bar

Hence, at the bottom of the well at $15^{o}C$ pressure is 309.8 bar.

6 0

3 years ago

Calculate the average reaction rate expressed in moles h2 consumed per liter per second

djyliett [7]

Answer:

Average rate of reaction expressed in moles H₂ consumed per liter per second = 0.0025 M/s = 0.0025 mol/L.s

Explanation:

The complete, correct Question, is presented in the attached image to this answer.

The average rate of reaction in terms of the reactant is defined as the total amount of reactant consumed over a period of time divided by total period of time.

Mathematically,

Average rate of reaction = (change in concentration of H₂ over a period of time) ÷ (total period of time)

Average rate of reaction = (-ΔC)/(Δt)

The minus sign is there because the concentration of reactants reduce with time.

change in concentration of H₂ = -ΔC

= -(0.02 - 0.03) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s

We could solve for the average rate of reaction expressed in moles Cl₂ consumed per liter per second

change in concentration of Cl₂ = -ΔC

= -(0.04 - 0.05) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s = 0.0025 mol/L.s

Hope this Helps!!!

8 0

3 years ago

Three functions of the stem​

Three functions of the stem