Consider the reaction 2X2Y+Z2⇌2X2YZ which has a rate law of rate= k[X2Y][Z2] Select a possible mechanism for the reaction. View
Available Hint(s) Consider the reaction which has a rate law of Select a possible mechanism for the reaction. A Step1:Step2:Step3:Z2→Z+Z (slow)X2Y+Z→X2YZ (fast) X2Y+Z→X2YZ (fast) B Step1:Step2:X2Y+Z2→X2YZ+Z (slow)X2Y+Z→X2YZ (fast) C Step1:Step2:X2Y+Z2→X2YZ2 (slow)X2YZ2→X2YZ+Z (fast) D Step1:Step2:2X2Y⇌X4Y2 (fast)X4Y2+Z2→2X2YZ (slow) E Step1:2X2Y+Z2→2X2YZ (slow)
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Answer: Equilibrium concentration of at
is 4.538 M
Explanation:
Initial concentration of = 0.056 M
Initial concentration of = 4.60 M
The given balanced equilibrium reaction is,
Initial conc. 0.056 M 4.60 M 0 M 0 M
At eqm. conc. (0.056-x) M (4.60-2x) M (x) M (6x) M
The expression for equilibrium constant for this reaction will be,
Given : equilibrium concentration of =x = 0.031 M
Concentration of = (4.60-2x) M =
=4.538 M
Thus equilibrium concentration of at
is 4.538 M
ANSWER
2 valence electrons
STEP-BY-STEP EXPLANATION:
The electronic configuration is given below as
Looking at the configuration, you will see that the last energy carries 2 electrons
Hence, the valence electrons are 2