Iconic compounds are electrolytes because they dissociate into ions when dissolved in water. Many molecules compounds are noneelectrolytes
The number of moles of hydrogen is equal to the number of moles of nitrogen.
According to the ideal gas equation
PV = nRT
where
- P = the pressure of the gas
- V = the volume of gas
- n = the total amount of ideal gas (moles)
- R = the universal gas constant
- T = the temperature
In the problems there are two identical cylinders means, V₁ = V₂
The pressure inside each of two identical cylinders is equal to atmospheric pressure means, P₁ = P₂
Both gases are at the same temperature, means T₁ = T₂


n₁ = n₂
So the total amount of hydrogen gas is equal to total amount of ideal nitrogen gas.
Learn more about the ideal gas equation here: brainly.com/question/27870704
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Answer:
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corrected by the one in the comment section
Answer: The volume of the balloon at the center of the typhoon is 41.7L.
Note: The complete question is given below;
If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?
The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.
Explanation:
Since no temperature changes were given, it is assumed to be constant. Therefore, Boyle's law which describes the relationship between pressure and volume is used to determine the new volume at the center of Typhoon Odessa. Mathematically, Boyle's law states that; P1V1 = P2V2
Assuming 1atm = 1 bar, 1mbar = 0.001atm, 40mbar = 0.040atm
P1 = 1.0atm, V1 = 40.0L, P2 = 1atm - 0.040atm = 0.960atm, V2 = ?
Using P1V1 = P2V2
V2 = P1V1/P2
V2 = 1.0 * 40.0 / 0.96
V2 = 41.67L
Therefore, the volume of the balloon at the center of the typhoon is 41.7L.
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