<u>Answer:</u> The mass percent of in the battery acid is 31.9 %
<u>Explanation:</u>
- To calculate the number of moles for given molarity, we use the equation:
We are given:
Molarity of solution =
Volume of solution = 35.05 mL
Putting values in above equation, we get:
- The chemical equation for the reaction of barium hydroxide and sulfuric acid follows the reaction:
By Stoichiometry of the reaction:
1 mole of barium hydroxide reacts with 1 mole of sulfuric acid
So, 0.00016 moles of barium hydroxide will react with = of sulfuric acid.
The calculated moles of sulfuric acid is present in 10 mL of solution.
To calculate the number of moles in 250 mL of solution, we use unitary method:
In 10 mL, the number of moles of sulfuric acid are 0.00016 moles
So, in 250 mL, the number of moles of sulfuric acid will be =
The calculated moles of sulfuric acid are present in 1 mL of solution.
- To calculate the number of moles, we use the equation:
Molar mass of sulfuric acid = 98 g/mol
Moles of sulfuric acid = 0.004 moles
Putting values in above equation, we get:
- To calculate the percentage composition of sulfuric acid in battery acid, we use the equation:
Mass of battery acid = 1.227 g
Mass of sulfuric acid = 0.398 g
Putting values in above equation, we get:
Hence, the mass percent sulfuric acid in battery acid is 31.9 %.