Question

Chris drops an egg with a parachute from the top of a building. The height, h, in feet, of the egg above the ground after t seconds is given
by h (t) = 100 - 16t2

After how many seconds does the egg hit the ground?

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Answer 1

Answer:

The egg hits the ground after 2.5 seconds.

Step-by-step explanation:

Height of the egg:

The height of the egg after t seconds is given by:

$h(t) = 100 - 16t^2$

After how many seconds does the egg hit the ground?

This is t for which $h(t) = 0$. So

$h(t) = 100 - 16t^2$

$16t^2 - 100 = 0$

$16t^2 = 100$

$t^2 = \frac{100}{16}$

$t = \sqrt{\frac{100}{16}}$

$t = \frac{10}{4}$

$t = 2.5$

The egg hits the ground after 2.5 seconds.