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2 years ago

HELP! FOR A TEST!

Physics

2 answers:

klio [65]2 years ago

7 0

Answer:

Acceleration

Explanation:

plato

Sati [7]2 years ago

4 0

Answer:

<h3>On a velocity vs time graph the slope of the line represents the acceleration of the object. With a slope of zero, the object is moving at a constant velocity in the positive (+) direction during this five minute interval. ... Displacement and distance can both be determine on a velocity vs.</h3>

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A 56 kg sprinter, starting from rest, runs 49 m in 7.0 s at constant acceleration.what is the sprinter's power output at 2.0 s,

alexgriva [62]

The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
$S= \frac{1}{2} a t^2$
where a is the acceleration. Using the data of the problem, we can find a:
$a= \frac{2S}{t^2} = \frac{2 \cdot 49 m}{(7.0 s)^2} =2.0 m/s^2$
So now we can solve the 3 parts of the problem.

a) power output at t=2.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(2.0 s)=4.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(4.0 m/s)^2=448 J$

and so the power output is
$P= \frac{E}{t} = \frac{448 J}{2.0 s} =224 W$

b) power output at t=4.0s
The velocity at t=4.0 s is
$v(t)=at=(2.0 m/s^2)(4.0 s)=8.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(8.0 m/s)^2=1792 J$

and so the power output is
$P= \frac{E}{t} = \frac{1792 J}{4.0 s} =448 W$

c) Power output at t=6.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(6.0 s)=12.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(6.0 m/s)^2=4032 J$

and so the power output is
$P= \frac{E}{t} = \frac{4032 J}{6.0 s} =672 W$

8 0

2 years ago

Ecologically speaking, which is bigger, a population or a community? Explain.

exis [7]

Here are a few of the fundamental words in ecology, which are simple, but may be easy to mix up because they are so similar. It is, however, quite important to be clear of what they mean. I will here try to explain how they differ by defining them and giving a few examples to illustrate how they could be applied.

A habitat is basically the site where an organism or a group lives. It may be anything from a stone in a lake, on which algae grows, to a forest containing all sorts of creatures. Note that groups within a habitat do not need to be of the same species. However, one usually speaks of habitats of individuals, species, or larger groups. For instance, the habitat of the algae would be the stone in the lake, and the forest could be the habitat of a single bear – regardless of what other organisms live there and how they are geographically distributed; here we are interested in the bear, so we define the habitat as its home range, and all that falls within it will arbitrarily be a apart of its habitat. hope this helps

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3 years ago

Read 2 more answers

A. A PH202 student lives next to a construction site and sees a crane with a wrecking ball demolish the building next door. The

netineya [11]

Answer:

The length of cable is 12.5 m

Explanation:

Since, the wrecking ball completes 1 oscillation, in the same time, as it takes for the rock to complete 5 oscillations.

Therefore,

Time Period of Wrecking Ball = 5 (Time Period of Rock)

Since,

Time Period of Pendulum = 2π√(L/g)

Therefore,

2π√(L₁/g) = 5[2π√(L₂/g)]

√L₁ = 5√L₂

Squaring on both sides:

L₁ = 25 L₂

where,

L₁ = Length of Cable = ?

L₂ = Length of string = 0.5 m

Therefore,

L₁ = 25 (0.5 m)

L₁ = 12.5 m

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3 years ago

Wind and water power are types of energy? A)renewable B)nonrenewable

Nastasia [14]

A. they are both a renewable energy

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3 years ago

the velocity (v) of a tranvas wave in a string is related to tension (T) the mass (M) and the length (L) of de string by the rel

Lana71 [14]

Explanation:

22u238uy832y978328993

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3 years ago