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Angelina_Jolie [31]
3 years ago
14

Is kicking a ball a conservation of momentum ?

Physics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

Yes, When the momentum and kinetic energy are conserved, as they are approximately conserved when kicking a ball, there is no loss in momentum and energy before or after the collision.

Hope this helps!

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Est ce qu’un cricket c’est un consommateur
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Answer:

Oui

Explanation:

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Which of the following is constant during uniform circular motion?
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An object undergoing <span>uniform circular motion </span>is moving with a constant speed. Nonetheless, it is accelerating due to its change in direction. So I'm thinking velocity
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Which is less likely to be a reliable source of information, the webpage of a university or the webpage of a scientist who is tr
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3 years ago
The average period of pendulum clock is found to be 1.2s at sea level. The period of the same pendulum on a mountain top is foun
Kipish [7]

Answer:

g' = 10.12m/s^2

Explanation:

In order to calculate the acceleration due to gravity at the top of the mountain, you first calculate the length of the pendulum, by using the information about the period at the sea level.

You use the following formula:

T=2\pi \sqrt{\frac{l}{g}}         (1)

l: length of the pendulum = ?

g: acceleration due to gravity at sea level = 9.79m/s^2

T: period of the pendulum at sea level = 1.2s

You solve for l in the equation (1):

l=\frac{gT^2}{4\pi^2}\\\\l=\frac{(9.79m/s^2)(1.2s)^2}{4\pi^2}=0.35m

Next, you use the information about the length of the pendulum and the period at the top of the mountain, to calculate the acceleration due to gravity in such a place:

T'=2\pi \sqrt{\frac{l}{g'}}\\\\g'=\frac{4\pi^2l}{T'^2}

g': acceleration due to gravity at the top of the mountain

T': new period of the pendulum

g'=\frac{4\pi^2(0.35m)}{(1.18s)^2}=10.12\frac{m}{s^2}

The acceleration due to gravity at the top of the mountain is 10.12m/s^2

5 0
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3 0
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