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2 years ago

Which ones are wrong?

Physics

1 answer:

Darya [45]2 years ago

6 0

None are incorrect, hope I could help.

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6th grade science !!!!!!!!!!!!!!!

posledela

Answer:

Explanation:

5 0

3 years ago

A block of mass m=9.0 kg and speed V and is behind a block of mass M= 27 kg and speed of .50 m/s. The surface is frictionless, a

sammy [17]

Answer:

2.06 m/s

Explanation:

From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.

Momentum before collision

Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5

Momentum after collision

The momentum after collision will be given by (9+27)*0.9=32.4

Relating the two then 9v+13.5=32.4

9v=18.5

V=2.055555555555555555555555555555555555555 m/s

Rounded off, v is approximately 2.06 m/s

5 0

3 years ago

A butcher grinds 5 and 3/4 lb of meat then sells it for 2 and 2/3 pounds to the customer what is the maximum amount me that the

KiRa [710]

Answer:

The maximum amount of meat that the butcher can sell is $3\frac{1}{12}\:lb$

Explanation:

The maximum amount can be found by taking the difference of mixed numbers.

$5\frac{3}{4}-2\frac{2}{3}\\\\\mathrm{Subtract\:the\:numbers:}\:5-2=3\\\\\mathrm{Combine\:fractions:\:}\frac{3}{4}-\frac{2}{3}=\frac{1}{12}\\\\=3\frac{1}{12}\\$

Best Regards!

8 0

3 years ago

A proton is propelled at 4×106 m/s perpendicular to a uniform magnetic field. 1) If it experiences a magnetic force of 4.8×10−13

tia_tia [17]

Answer:

B = 0.75 T

Explanation:

As we know that the force on a moving charge in magnetic field is given by the formula

$F = qvB$

here we have

$B = \frac{F}{qv}$

here we know that

$F = 4.8 \times 10^{-13} N$

$q = 1.6 \times 10^{-19} C$

$v = 4 \times 10^6 m/s$

now from above equation we have

$B = \frac{4.8 \times 10^{-13}}{(1.6 \times 10^{-19})(4 \times 10^6)}$

$B = 0.75 T$

8 0

3 years ago

Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she

Alex777 [14]

Answer

$200km {h}^{ - 2}$

Explanation

$Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2}$

Hope this helps you.

Let me know if you have any other questions :-):-)

6 0

3 years ago

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