Answer:
<h2>
206.67N</h2>
Explanation:
The sum of force along both components x and y is expressed as;

The magnitude of the net force which is also known as the resultant will be expressed as 
To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.
Given the position of the object along the x-component to be x = 6t² − 4;


Similarly,



Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N
Answer:

Explanation:
<u>Motion With Constant Acceleration
</u>
It's a type of motion in which the velocity of an object changes uniformly over time.
The equation that describes the change of velocities is:

Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
Solving the equation for a:

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.
The acceleration is:


Answer:
v = 7.67 m/s
Explanation:
Given data:
horizontal distance 11.98 m
Acceleration due to gravity 9.8 m/s^2
Assuming initial velocity is zero
we know that

solving for t
we have

substituing all value for time t

t = 1.56 s
we know that speed is given as


v = 7.67 m/s
Mutualism is a long-term relationship where two organisms interact in such a way that both of them benefits from that relationship.
For example, there is a relationship between a bird called "oxpecker", and a rhino. While the bird eats the harmful bugs (eg. tick) on the rhino's skin and relieves its hunger; the rhino gets rid of the bugs that harm it.
Answer:
the time taken for the automobile to travel the given distance is 80 mins.
Explanation:
Given;
speed of the automobile, v = 30 km/h
distance traveled by the automobile, x = 40 km
The time taken for the automobile to cover the given distance is calculated as;
time = distance / speed
time = 40 / 30
time = 1.3333 hours = 1.3333 hr x 60mins/hr = 80 mins
Therefore, the time taken for the automobile to travel the given distance is 80 mins.