<span>6.6 degrees C
Let's model the student as a 125 w furnace that's been operating for 11 minutes. So
125 w * 11 min = 125 kg*m^2/s^3 * 11 min * 60 s/min = 82500 kg*m^2/s^2 = 82500 Joule
So the average kinetic energy increase of each gas molecule is
82500 J / 6.0x10^26 = 1.38x10^-22 J
Now the equation that relates kinetic energy to temperature is:
E = (3/2)Kb*Tk
E = average kinetic energy of the gas particles
Kb = Boltzmann constant (1.3806504Ă—10^-23 J/K)
Tk = Kinetic temperature in Kelvins
Notice the the energy level of the gas particles is linear with respect to temperature. So we don't care what the original temperature is, we just need to know by how much the average energy of the gas particles has increased by.
So let's substitute the known values and solve for Tk
E = (3/2)Kb*Tk
1.38x10^-22 J = (3/2)1.3806504Ă—10^-23 J/K * Tk
1.38x10^-22 J = 2.0709756x10^-23 J/K * Tk
6.64 K = Tk
Rounding to 2 significant digits gives 6.6K. So the temperature in the room will increase by 6.6 degrees K or 6.6 degrees C, or 11.9 degrees F.</span>
Answer:
weight
Explanation:
weight is the pull of gravity so its a force !!
Answer:
The first one with the big plus in the middle and negatively charged electrons around.
Explanation:
