Question

The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to slow to a final velocity of 2.0 m/s?

Answer 1

Answer:

t = 2.35s

Explanation:

Using one of the equation of motion expressed as v = u+at where;

v is the final velocity = 2.0m/s

u is the initial velocity = 25m/s

a is the acceleration = -a (since the acceleration is negative)

t is the time taken

Substituting the given parameters into the formula above;

2.0 = 25-9.81t

subtract 25 from both sides

2.0 - 25 = 25-9.81t - 25

-23 = -9.81t

Divide both sides by -9.81

-23/-9.81 = -9.81t/-9.81

t = 23.0/9.81

t = 2.35s

Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s