3 years ago

I don’t understand this , can someone help

Mathematics

1 answer:

Llana [10]3 years ago

8 0

Answer:

The relation DOES represent a function.

Step-by-step explanation:

To determine whether a graph is a function or not use the vertical line test.

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Given:<br> f(x)=x^2<br> g(x)=x-1<br> Find f(g(2))+g(f(-1))

Marina CMI [18]

Answer:

-1

Step-by-step explanation:

First, we need to work out the left-hand side.

find g(2) → g(2) = 2 - 1 which is 1
next, find f(1) → f(1) = 1³ which is 1

Now, we can work out the right hand side.

find f(-1) → f(-1) = -1³ which is -1
then, find g(-1) → g(-1) = -1 - 1 = -2

Finally we can work out the full sum: 1 + -2 = -1.

Hope this helps!

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3 years ago

A movie rental company charges a yearly membership fee of $18.Each movie rental is $1.50.Which equation could be used to find th

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Answer:

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Step-by-step explanation:

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4 years ago

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3 years ago

A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

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3 years ago

The equation of a circle is (X+12)^2+(y+16)^2=r^2, and the circle passes through the origin. The equation of the circle then cha

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Answer:

$x=\sqrt{r_{2} +y-16(r2-y+16)+30}$ R2

$r=\sqrt{x^2+24x+y2+32y+400}$

Step-by-step explanation:

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3 years ago