5 miles on Thursday, with one mile=5,280 ft. You do 5 multipled by 5,289 which you get 26,499
First, think of your places. You have the ones places, tens places, hundreds places, and so on.
The first number starting from the right is the ones, and as you keep going left, the value of each given digit becomes higher.
Since 5 is in the ones place, its value would be just 5. If it were in the tens place, it would be 50. If it were in the hundreds place, it would be 500, and so on.
Think of it this way;
Ones is just one. If a number is in the 'ones' place, its value would be a single digit. If it were in the tens place, its value would be two digits.
That's how it would be for each place going left.
Every number you move to the left, its value gains a one.
So here's an example:
5555
The value of 5 in the ones place "5555" is simply 5.
In the tens place, you end up adding one zero, so the value of the second five to the left would be, "50"
So with that said, the value of the digit 5 in the number 75 is <em>5.
</em>Haha, hope this cleared up any confusion, and have a <em>wonderful </em>day! :)<em>
</em>
Hello!
This question is about which values you are changing when you are transforming an equation.
Let's go through the parent function for an absolute value equation and its various transformations.

Since we are only looking at horizontal and vertical transformations, we only need to worry about the c and d values.
The c value of a function determines a function's horizontal position, and the d value of a function determines a function's vertical position.
One thing to note here is that the c value is being subtracted from the x value, meaning that if the function is being transformed to the right, you would actually be subtracting that value, while the d value behaves like a normal value, if it is being added, the function is transformed up, and vice versa.
Now that we know this, let's write each expression.
a) 
b) 
c) 
d) 
Hope this helps!
Greetings.
The range is the set of y-value.
The range starts from the minimum point to maximum point.
Our minimum point starts at 0 and maximum point starts less than infinity.
Therefore the range is 0<=y<+inf
However, we do not often write that, although it is right.
Therefore we write as y≥0
Thus, the answer is B choice.