What is the electronic configuration of the atom x

The smell of dirty gym socks is caused by the compound caproic acid(contains H, C, O). Combustion of 0.844 g of caproic acid pro

adoni [48]

Answer: The molecular formula for the given organic compound is $C_2H_{32}O_4$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.784g$

Mass of $H_2O=1.92g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.784 g of carbon dioxide, $\frac{12}{44}\times 0.784=0.214g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.92 g of water, $\frac{2}{18}\times 1.92=0.213g$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.844) - (0.214 + 0.213) = 0.417 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.214g}{12g/mole}=0.0134moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.213g}{1g/mole}=0.213moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.417g}{16g/mole}=0.0261moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0134 moles.

For Carbon = $\frac{0.0134}{0.0134}=1$

For Hydrogen = $\frac{0.213}{0.0134}=15.89\approx 16$

For Oxygen = $\frac{0.0261}{0.0134}=1.95\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 16 : 2

The empirical formula for the given compound is $CH_{16}O_2$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 116.2 g/mol

Mass of empirical formula = 60 g/mol

Putting values in above equation, we get:

$n=\frac{116.2g/mol}{60g/mol}=1.94\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 2)}H_{(16\times 2)}O_{(2\times 2)}=C_2H_{32}O_4$

Hence, the molecular formula for the given organic compound is $C_2H_{32}O_4$

5 0

3 years ago

On hot days, you may have noticed that potato chip bags seem to "inflate", even though they have not been opened. If I have a 25

Slav-nsk [51]

The new volume of the bag will be 789.5 mL.

Explanation:

As per the Charles law, at constant pressure the volume of the gas is directly related to its temperature in Kelvin (K). That is as the temperature increases, the gas expands and vice-versa.

$$\frac{V1}{T1} = \frac{V2}{T2}\\$

V1 = 250 ml

V2 = ?

T1 = 19° C

T2 = 60° C

Now we have to rewrite the equation to get the new volume as,

V2 = $$\frac{V1T2}{T1}$

= $$\frac{250\times60}{19}$

= 789.47 ≈ 789.5 ml.

So the new volume of the bag will be 789.5 mL.

7 0

3 years ago

All the following steps need to be followed when naming alkanes, except

goldfiish [28.3K]

A.

Begin numbering at the end closest to the first branch, not the farthest.

6 0

4 years ago

Read 2 more answers

A benefit of using nuclear energy could be the abundance of uranium in nature. Which human risk about mining is the most importa

Murrr4er [49]

The health hazards because it is asking which human risk is the most important to consider.

5 0

3 years ago

Read 2 more answers

If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at a constant temperature. What is the new volume

wel

Answer :

=748

⋅22.5

725

=23.2L

3 0

4 years ago

What is the electronic configuration of the atom x​

What is the electronic configuration of the atom x