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Marizza181 [45]
3 years ago
14

0.159 mol 2.25 M = A L of HCI

Chemistry
2 answers:
mylen [45]3 years ago
4 0
Answer will be
0.159 mol
2.25 M
= A L of HCI
.0707

Hope this helps.
Verizon [17]3 years ago
3 0

Answer:

hmmm?what?

Explanation:

ayusin mo flece:>

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A sample of sulfurous acid (H2SO3) has a mass of 1.31 g.
lakkis [162]

Answer:

a) 2 (H+) ions

b) 1 (SO3²-) ions

c) 1.36 × 10^-22 grams.

Explanation:

According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.

Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:

2H+ + SO3²- → H2SO3

Hence;

- there are 2 hydrogen ions (2H+) present in H2SO3.

- there is 1 sulfite ion (SO3²-) present in H2SO3.

c) The mass of one formula unit of H2SO3 is calculated thus:

= 1.008 (2) + 32.065 + 15.999(3)

= 2.016 + 32.065 + 47.997

= 82.08 a.m.u

Since, 1 gram is = 6.02 x 10^23 a.m.u

82.08 a.m.u = 82.08/6.02 × 10^-23

= 13.6 × 10^-23

= 1.36 × 10^-22 grams.

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3 years ago
Which of the following sentences best describes what is shown in the above picture?
velikii [3]

Answer:

Cells of a multicellular organism

5 0
3 years ago
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Viết công thức hóa học tạo bởi Mg và O
jasenka [17]
Phương trình hóa học: 2Mg+O2->2Mgo
3 0
3 years ago
Use the balanced equation given below to solve the following problem; Calculate the volume in liters of CO produced by the react
Elan Coil [88]

Answer: 40.3 L

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} Sb_2O_3=\frac{175g}{291.5g/mol}=0.600moles

Sb_2O_3+3C\rightarrow 2Sb+3CO  

According to stoichiometry :

1 moles of Sb_2O_3 produces = 3 moles of CO

Thus 0.600 moles of Sb_2O_3 will produce=\frac{3}{1}\times 0.600=1.80moles  of CO

Volume of CO=moles\times {\text {Molar volume}}=1.80moles\times 22.4L/mol=40.3L

Thus 40.3 L of CO is produced.

6 0
3 years ago
Observation and assessment are most effective when
Artist 52 [7]
I think the answer is A. Hope that helped :)
6 0
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