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PIT_PIT [208]
2 years ago
14

A sample of sulfurous acid (H2SO3) has a mass of 1.31 g.

Chemistry
1 answer:
lakkis [162]2 years ago
6 0

Answer:

a) 2 (H+) ions

b) 1 (SO3²-) ions

c) 1.36 × 10^-22 grams.

Explanation:

According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.

Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:

2H+ + SO3²- → H2SO3

Hence;

- there are 2 hydrogen ions (2H+) present in H2SO3.

- there is 1 sulfite ion (SO3²-) present in H2SO3.

c) The mass of one formula unit of H2SO3 is calculated thus:

= 1.008 (2) + 32.065 + 15.999(3)

= 2.016 + 32.065 + 47.997

= 82.08 a.m.u

Since, 1 gram is = 6.02 x 10^23 a.m.u

82.08 a.m.u = 82.08/6.02 × 10^-23

= 13.6 × 10^-23

= 1.36 × 10^-22 grams.

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Explanation:

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Consider the following reaction.
Ivan

Answer:

162 g Fe₂O₃

Explanation:

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Molar Mass (C): 12.011 g/mol

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Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

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--------------  x  ----------------  x  -------------------------  x  -----------------  = 162 g Fe₂O₃
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5 0
1 year ago
To answer this question, you will need to write the balanced equation and set up a BCA table. Using appropriate rounding rules,
Elenna [48]

Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.

BCA table:

2H_{2}O ⇒ H_{2} + O_{2}

B  0.13        0 + 0

C  -0.13      0.065 + 0.065

A  0             0.065

Explanation:

Balanced equation for water decomposition into hydrogen and oxygen gases

   2H_{2}O ⇒ H_{2} + O_{2}

B  0.13        0 + 0

C  -0.13      0.065 + 0.065

A  0             0.065

Number of moles of water = \frac{mass}{atomic mass of 1 mole}

mass = 2.5 grams

atomic mass= 18 grams

number of moles can be known by putting the values in the formula,

n = \frac{2.5}{18}

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2 moles of water gives one mole of oxygen on decomposition

so, 0.13 moles of water will give x moles of oxygen on decompsition

\frac{1}{2} = \frac{x}{0.13}

x = 0.065 moles of oxygen will be formed.

moles to gram will be calculated as

mass =number of moles x atomic mass

        = 0.065 x 16

         = 1.04 grams of oxygen.

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stepladder [879]
This is a tough one but the answer is water

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6 0
2 years ago
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