Answer:
Striped should be the answer
Answer:
The answer to your question is empirical formula Al₃O₉S
Explanation:
Data
Al = 31.5 %
O = 56.1 %
S = 12.4 %
Process
1.- Look for the atomic masses of the elements
Al = 27 g
O = 16
S = 32
2.- Represent the percentages as grams
Al = 31.5 g
O = 56.1 g
S = 12.4 g
3.- Convert these masses to moles
27 g of Al ----------------- 1 mol
31.5 g ---------------------- x
x = 1.17 moles
16 g of O ---------------- 1 mol
56.1 g of O ------------- x
x = 3.5 mol
32 g of S --------------- 1 mol
12.4 g of S ------------- x
x = 0.39 moles
4.- Divide by the lowest number of moles
Al = 1.17 / 0.39 = 3
O = 3.5 / 0.39 = 8.9 ≈ 9
S = 0.39 / 0.39 = 1
5.- Write the empirical equation
Al₃O₉S
Answer:
air,water,and food.
Explanation:
Some animals need to obtain their energy from plants.
Carbon dioxide is a gas at normal room temperature and atmospheric pressure. Carbon dioxide gas converts into solid carbon dioxide when frozen to a particular temperature with no intermediate liquid phase. This frozen or solidified carbon dioxide is called dry ice. Dry ice is formed when gaseous carbon dioxide is cooled to very low temperatures under high pressure. High pressure brings about condensation of the gas molecules and low temperature solidifies the carbon dioxide gas. Therefore, tow factors that help in formation of dry ice are low temperature and high pressure.
