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rewona [7]
3 years ago
9

12. What is the empirical formula for C10H30O5?

Chemistry
1 answer:
kramer3 years ago
5 0

Answer:

Just use a text book.. So that you get the concept

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The net charge on a sulfide ion (s2-) is -2. explain how this ion obtains its charge
Anestetic [448]
Sulfur is a group six element in period 3 with atomic number 16 and an electronic configuration of 2:8:6. Therefore, to attain a stable configuration it requires to gain two electrons forming an ion with a charge of -2. The negative charge is due to the gaining of electrons.
6 0
2 years ago
Which of the following statements is true? A) The iron atom is best considered to be a solid. B) The mercury atom is best consid
shepuryov [24]
I believe the correct response would be D. At least 2 of the above statements are correct.
3 0
3 years ago
Read 2 more answers
Which symbol in a chemical equation separates the reactants from the products ?
Lana71 [14]

Answer:

Explanation:

The arrow symbol in a chemical equation separates the reactants from products. A chemical reaction is process in which chemical changes leads to the formation of products from reactants.

4 0
3 years ago
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Four atoms are arbitrarily labeled D, E, F, and G. Their electronegativities are as follows: D = 3.8, E = 3.3, F = 2.8, and G =
PSYCHO15rus [73]

Answer:

Thus the order of covalent character will be

DG < EG < DF < DE

Explanation:

The electronegativity decides the nature of bond formed between two atoms.

More the difference in electronegativity more the ionic character in the bond formed.

Let us check the electronegativity difference between the elements forming molecules

a) DE :

3.8-3.3 = 0.5

b) DG :

3.8-1.3 = 2.5

c) EG

3.3-1.3 = 2

d) DF

3.8-2.8 = 1.3

So the maximum ionic character will be in DG and minimum in DE

Thus the order of covalent character will be

DG < EG < DF < DE

3 0
3 years ago
8) 4.00 mol HI are placed in an evacuated 5.00 L flask and then heated to 800 K. The system is allowed to reach equilibrium. Det
SVEN [57.7K]

Answer: Concentration of H_2 at equilibrium = 0.08 M

Concentration of I_2 at equilibrium =0.08 M

Concentration of Hl = 0.64M

Explanation:

Moles of  HI = 4.00 mole

Volume of solution = 5.00 L

Initial concentration of HI =\frac{moles}{Volume}=\frac{4.00mol}{5.00L}=0.8M

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

For the given chemical reaction:

         2HI(g)\rightarrow H_2(g)+I_2(g)

Initial conc.      0.8 M           0 M    0 M

   At eqm. conc.  (0.8-2x) M   (x) M   (x) M    

The expression for K_c is written as:

K_c=\frac{[H_2]^1[I_2]^1}{[HI]^2}

0.016=\frac{(x)\times (x)}{(0.8-2x)}

x=0.08M

Concentration of H_2 at equilibrium = x M = 0.08 M

Concentration of I_2 at equilibrium = x M = 0.08 M

Concentration of Hl = (0.8-2x) = (0.8-2\times 0.08)M= 0.64M

3 0
3 years ago
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