Question

A 16 gram sample of O2(g) fills a container at STP. What volume is the container?

Answer 1

Answer:

V = 11.2 L

Explanation:

Hello there!

In this case, according to the ideal gas equation:

$PV=nRT$

It is possible to compute the volume as shown below:

$V=\frac{nRT}{P}$

Whereas the moles are computed are computed given the mass and molar mass of oxygen:

$n=16g*\frac{1mol}{32g} =0.5mol$

Now, since the STP stands for a temperature of 273.15 K and a pressure of 1 atm, the resulting volume is:

$V=\frac{0.5mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=11.2L$

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