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BartSMP [9]
3 years ago
12

The balanced equation below shows the products that are formed when butane (C4H10) is combusted. 2C4H10 + 13O2 mc009-1.jpg 8CO2

+ 10H2O
What is the mole ratio of butane to carbon dioxide?

1.)1:4
2.)1:5
3.)13:8
4.)13:10
Chemistry
2 answers:
valentinak56 [21]3 years ago
8 0

Answer:

1:4

Explanation:

Verizon [17]3 years ago
6 0
The correct answer would be option 1. The mole ratio of butane to carbon dioxide is 1:4. Looking at the balanced chemical reaction, we see that we need 2 moles of butane to produce 8 moles of carbon dioxide. So, it is 2:8. Simplifying this by dividing both to 2, we have 1:4.
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<u>Answer:</u>

<u>For A:</u> The K_p for the given reaction is 4.0\times 10^1

<u>For B:</u> The K_c for the given reaction is 1642.

<u>Explanation:</u>

The given chemical reaction follows:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

  • <u>For A:</u>

The expression of K_p for the above reaction follows:

K_p=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}

We are given:

p_{NOCl}=0.24 atm\\p_{NO}=9.10\times 10^{-2}atm=0.0910atm\\p_{Cl_2}=0.174atm

Putting values in above equation, we get:

K_p=\frac{(0.24)^2}{(0.0910)^2\times 0.174}\\\\K_p=4.0\times 10^1

Hence, the K_p for the given reaction is 4.0\times 10^1

  • <u>For B:</u>

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure = 4.0\times 10^1

K_c = equilibrium constant in terms of concentration = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 500 K

\Delta ng = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

4.0\times 10^1=K_c\times (0.0821\times 500)^{-1}\\\\K_c=\frac{4.0\times 10^1}{(0.0821\times 500)^{-1})}=1642

Hence, the K_c for the given reaction is 1642.

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Answer:

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