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BartSMP [9]
2 years ago
12

The balanced equation below shows the products that are formed when butane (C4H10) is combusted. 2C4H10 + 13O2 mc009-1.jpg 8CO2

+ 10H2O
What is the mole ratio of butane to carbon dioxide?

1.)1:4
2.)1:5
3.)13:8
4.)13:10
Chemistry
2 answers:
valentinak56 [21]2 years ago
8 0

Answer:

1:4

Explanation:

Verizon [17]2 years ago
6 0
The correct answer would be option 1. The mole ratio of butane to carbon dioxide is 1:4. Looking at the balanced chemical reaction, we see that we need 2 moles of butane to produce 8 moles of carbon dioxide. So, it is 2:8. Simplifying this by dividing both to 2, we have 1:4.
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shusha [124]

Answer: its C. and B.

Explanation:

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3 0
2 years ago
B) How many kilograms of carbon dioxide are formed when 24.42 g of iron is<br> produced?
charle [14.2K]

Answer:

0.0289 kg of CO2 will be formed

Explanation:

Step 1: Data given

Mass of iron produced = 24.42 grams

Atomic mass iron = 55.845 g/mol

Molar mass CO2 = 44.01 g/mol

Step 2: The balanced equation

Fe2O3 + 3CO → 2Fe + 3CO2

Step 3: Calculate moles iron

Moles iron = mass iron / molar mass iron

Moles iron = 24.42 grams / 55.845 g/mol

Moles iron = 0.437 moles

Step 4: Calculate moles CO2

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.437 moles Fe we'll have 3/2 * 0.437 = 0.6555 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.6555 moles * 44.01 g/mol

Mass CO2 = 28.85 grams = 0.0289 kg

0.0289 kg of CO2 will be formed

5 0
3 years ago
The ________ orbital is degenerate with 5py in a many-electron atom.
arsen [322]

The ________ orbital is degenerate with 5py in a many-electron atom.


<h2>5px is the correct answer</h2>
5 0
3 years ago
How are electric circuits like water in pipes list two ways
____ [38]
They flow through the inslation of the house .

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8 0
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El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si
Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)

Lo cual hace que la expresión de equilibrio se calcule como:

Ksp=[Pb^{2+}][Cl^-]^2

Y que en términos de la solubilidad molar, s, se resuelve como:

1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L

¡Saludos!

7 0
2 years ago
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