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Grace [21]
3 years ago
13

Pls help 2-3 tyvm ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer:

I could I guess?

But like only 1 lol

Explanation:

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What is the Molarity of a solution with 1.8 mil KCl dissolved to a volume of 1.5L
vova2212 [387]

Answer:1.2M

Explanation:

Molarity=number of moles ➗ volume in liters

Molarity=1.8 ➗ 1.5

Molarity=1.2M

8 0
3 years ago
I have 1.30 atm of gas in a piston at a temperature of 250°C. If I cool the gas until the
Setler [38]

Answer:

epppppp000.55.1

Explanation:

Hi and please let me know if you need anything else from me please let me know if you need anything

4 0
3 years ago
Lucy had two samples of different iron ores, haematite and magnetite.
Kaylis [27]

Answer:

magnetite

Explanation:

proportion of iron in haematite = 3.5/5 x 100% = 70%

proportion of iron in magnetite = 7.2/10 x 100% = 72%

7 0
3 years ago
Uranium is used in nuclear reactors and is a rare element on earth. Uranium has three common isotopes. If the abundance of 234U
LenaWriter [7]

Answer:

Average atomic mass of uranium= 237.98 amu.

Explanation:

Given data:

Abundance of U²³⁴ = 0.01%

Abundance of U²³⁵ = 0.17%

Abundance of U²³⁸ = 99.28%

Average atomic mass = ?

Solution:

Average atomic mass of uranium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass of uranium= (234×0.01)+(235×0.71)+(238×99.28)/100

Average atomic mass of uranium=  2.34 + 166.85 + 23628.64 / 100

Average atomic mass of uranium= 23797.83 / 100

Average atomic mass of uranium= 237.98 amu.

3 0
3 years ago
I need help with my chemistry homework. SHOW WORK
Veronika [31]

1) The gold will occupy a volume of 2.99 dm³.


\text{Volume = 17 200 g} \times \frac{\text{1 cm}^{3}}{\text{5.75 g}} = \text{2990 cm}^{3} = \textbf{2.99 dm}^{3}\\

2) The density of the olive oil is 0.850 g/cm³.

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{425 g}}{\text{500 cm}^{3}}= \textbf{0.850 g/cm}^{3}

3) The mass of the silver is 10.4 kg.

\text{Mass} = \text{987 cm}^{3} \times \frac{\text{10.5 g} }{\text{1 cm}^{3 }} = \textbf{10 400 g = 10.4 kg}\\

3 0
3 years ago
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