M(KNO₃)=101.1 g/mol
M(CO(NH₂)₂)=60.1 g/mol
m(N)=M(N)m(KNO₃)/M(KNO₃)
m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂)
2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)
m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃))
m(CO(NH₂)₂)=60.1*101.1/(2*101.1)=30.05 g
Answer:
Explanation:
This question involves the conversion of mass into energy: E = mc².
e + p ⟶ γ + γ
Each particle has the same mass so, in terms of mass, we can write
2e ⟶ 2γ or
e ⟶ γ
Thus, we can just convert the mass of an electron to its energy equivalent.
(a) Energy in joules
(b) Energy in kilojoules per mole
(c) Energy in electron volts
Answer:
(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.
Explanation:
According to the Kelvin–Planck statement of the second law of thermodynamics ,it is not possible to construct a device which operates in cycle and does not produce effect on the environment than the production of work.
We know that
Coefficient of performance is the ratio of desired effect to the work input in a cycle.
Given all option is correct but most appropriate option is a.
So the option a is correct
(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.
Answer:
Q = 1.44×10⁴ J
Explanation:
Given data:
Mass of water = 62.5 g
Initial temperature = 25.5°C
Final temperature = 80.7°C
Specific heat capacity of water = 4.184 J/g.K
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 80.7°C - 25.5°C
ΔT = 55.2 °C
Q = 62.5 g × 4.184 J/g.°C × 55.2 °C
Q = 14434.8 J
Q = 1.44×10⁴ J