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mojhsa [17]
3 years ago
10

How does heat transfer? (Think temperature)​

Physics
1 answer:
yulyashka [42]3 years ago
5 0

Answer:

The rate at which temperature changes is proportional to the rate at which heat is transferred.

Explanation:

The temperature of a sample changes more rapidly if heat is transferred at a high rate and less rapidly if heat is transferred at a low rate

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Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fi
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Answer:

The tabletop is smooth so my finger is down it fast and easy. The fabric however slowed my finger down considerably, and it was harder for me to move my finger across it.

Explanation:

Hope this helps.

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An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complet
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Answer:

The acceleration due to gravity at Pluto is 0.0597 m/s^2.

Explanation:

Length, L = 1 m

10 oscillations in 257 seconds

Time period, T = 257/10 = 25.7 s

Let the acceleration due to gravity is g.

Use the formula of time period of simple pendulum

T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2

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3 years ago
We all have a tendency to make illusory correlations from time to time. Try to think of an illusory correlation that is held by
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2 years ago
A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.
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2 years ago
A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho
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Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f

There is no kinetic energy in the initial state, nor potential energy in the end,

mgh+0=0+KE_f

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)

The inertia of the bodies is given by the equation,

I=\frac{m(R_1^2+R^2_2)}{2}

I=\frac{2(0.2^2+0.1^2)}{2}

I=0.05Kgm^2

On the other hand the angular velocity is given by

\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s

Replacing these values in the equation,

(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2

Solving for h,

h=2.86m

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3 years ago
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