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Vinvika [58]
3 years ago
6

Based on the thermodynamic functions of enthalpy and entropy, can an unfavorable reaction that has a positive δg at rt be made f

avorable by increasing the reaction temperature?
Physics
1 answer:
Over [174]3 years ago
7 0
I believe that the answer to the question provided above is yes, an unfavorable reaction that has a positive δg at rt be made favorable by increasing the reaction temperature.
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.
GalinKa [24]

Answer:

The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

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3 years ago
Where did the element heavier than hydrogen and helium come from?
Snezhnost [94]

They were produced inside stars.

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3 years ago
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What is the pendulum length whose period is 2.0s ?
Mashutka [201]
Formula\ for\ period:\\\ T=2 \pi \sqrt{\frac{L}{g}}\\\ g-gravity=9,8 \frac{m}{s^2} ,\ L-pendulum \ length \\\\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\\\\ \frac{T^2}{2 \pi }*g=L\\\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24mT=2 \pi   \sqrt{\frac{L}{g}} \\
 \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\
 \frac{T^2}{2 \pi }  = \frac{L}{g} \\
 \frac{T^2}{2 \pi }*g=L\\
L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m

7 0
3 years ago
Un móvil se desplaza con movimiento uniforme con una rapidez de 36 Km/h ¿Cuál es la distancia recorrida al cabo de 0,5 horas?
Diano4ka-milaya [45]

Answer:

Distancia = 17,5 kilómetros.

Explanation:

Dados los siguientes datos;

Velocidad = 36 km/h

Tiempo = 0.5 horas

Para encontrar la distancia recorrida;

Distancia = velocidad * tiempo

Distancia = 35 * 0.5

Distancia = 17,5 kilómetros.

Por tanto, la distancia recorrida por el automóvil es de 17,5 kilómetros.

4 0
3 years ago
A crane lifts a load of 15000N to a height 40m in 50 seconds. Calculate the power of the crane​
Nataly [62]

Answer:

P = 12000 W

Explanation:

General data:

  • F = 15000 N
  • d = 40 m
  • t = 50 s
  • P = ?

Work is force times unit of distance. So in order to calculate the power we must first calculate the work.

Formula:

  • \boxed{\bold{W=\frac{F}{d}}}

Replace and solve

  • \boxed{\bold{W=\frac{15000\ N}{40\ m}}}
  • \boxed{\bold{W=600000\ J}}

once the work is found, we proceed to find the power according to the formula:

  • \boxed{\bold{P=\frac{W}{t}}}
  • \boxed{\bold{P=\frac{600000\ J}{50\ s}}}
  • \boxed{\boxed{\bold{P=12000\ W}}}

The power of the crane is <u>12000 Watts.</u>

Greetings.

6 0
3 years ago
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