Answer:
The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V
Explanation:
As the complete question is not given the complete question is found online and is attached herewith.
By applying KCL at node 1

Also

Now applying KVL on loop 1 as indicated in the attached figure

Similarly for loop 2

So the system of equations become

Solving these give the values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA. Also the value of voltage is given as

The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V
Answer:
See attached image for diagrams and solution
Answer:
Energy stored in the capacitor will increase first, and then it will decrease.
Explanation:
Answer:
Okay I understand the situation, however, you must make the question more clear.
Explanation: