Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Since the average height is 60 inches and its deviation is 2 inches, one deviation to the right (or higher) is 62 inches (60 + 2). Two deviations is 64 inches, three deviations is 66 inches, and four deviations is 68 inches.
Since the average weight is 100 pounds and its deviation is 5 inches, we repeat the process from finding heights to get to 115 pounds. That takes three deviations.
The MORE deviations away, the more unusual it is. So the height (4 deviations) is more unusual than the weight (3 deviations).
Answer:
C
Step-by-step explanation:
Answer:
Therefore the width is 25 feet for getting maximum area.
The maximum area of the rectangle is 625 square feet.
Therefore the range is 0≤A≤625.
Step-by-step explanation:
Given function is
A = - x²+50x
We know that ,
If y = ax²+bx+c
For the maximum 
Here a = -1 , b= 50 and c=0
Therefore the width 
Therefore the width is 25 feet for getting maximum area.
The maximum area =[ -(25)²+50.25] square feet
= 625 square feet
The area can not be negative and maximum area is 625 square feet.
Therefore the range is 0≤A≤625.
Answer: Simple, it got Translated according to the rule (x, y) → (x + 2, y + 8) and reflected across the y-axis
Step-by-step explanation:
