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Gemiola [76]
3 years ago
13

HELP WILL MEDAL!!!! HELP

Physics
1 answer:
steposvetlana [31]3 years ago
8 0
Here try this. The pic is the answer

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Momentum of an object is determined to be 7.2 ×10 to the negative 3 kg
abruzzese [7]
Answer:

0.0072

Explanation

7.2x10^-3= 0.0072
6 0
3 years ago
An uncharged series RC circuit is to be connected across a battery. For each of the following changes, determine whether the tim
slavikrds [6]

a) Increase

b) Unchanged

c) Increase

Explanation:

a)

The charge on a capacitor charging in a RC circuit connected to a battery follows the exponential equation:

Q(t)=Q_0 (1-e^{-\frac{t}{RC}})

where

Q_0 = CV is the final charge stored in the capacitor, where C is the capacitance and V is the voltage of the battery

t is the time

R is the resistance of the circuit

The capacitor reaches 90% of its final charge when

Q(t)=0.90Q_0

Substituting and re-arranging the equation, we find:

0.90Q_0 = Q_0(1-e^{-\frac{t}{RC}})\\0.90=1-e^{-\frac{t}{RC}}\\e^{-\frac{t}{RC}}=0.10\\-\frac{t}{RC}=ln(0.10)\\t=-RCln(0.10)=2.30RC

We see that if we double the RC constant, then (RC)'=2(RC)

So the time taken will double as well:

t'=2.30(RC)'=2.30(2RC)=2(2.30RC)=2t

So, the answer is "increase"

b)

In this second part, the battery voltage is doubled.

According to the equation written in part a),

Q_0 =CV

this means also that the final charge stored on the capacitor will also double.

However, the equation that gives us the time needed for the capacitor to reach 90% of its full charge is

t=2.30 RC

We see that this equation does not depend at all on the voltage of the battery.

Therefore, if the battery voltage is doubled, the final charge on the capacitor will double as well, but the time needed for the capacitor to reach 90% of its charge will not change.

So the correct answer is

"unchanged"

c)

In this case, a second resistor is added in series with the original resistor of the circuit.

We know that for two resistors in series, the total resistance of the circuit is given by the sum of the individual resistances:

R=R_1+R_2

Since each resistance is a positive value, this means that as we add new resistors, the total resistance of the circuit increases.

Therefore in this problem, if we add a resistor in series to the original circuit, this means that the total resistance of the circuit will increase.

The time taken for the capacitor to reach 90% of its final charge is still

t=2.30 RC

As we can see, this time is directly proportional to the resistance of the circuit, R: therefore, if we add a resistor in series, the resistance of the circuit will increase, and therefore this time will increase as well.

So the correct answer is

"increase"

8 0
3 years ago
A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o
Furkat [3]
            <span> Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

</span>
4 0
3 years ago
Read 2 more answers
In this section of a circuit, a current of 2.0 A flows across R1. What is the current across R2? Let R1 = 4.0 ohm, R2 = 8.0 ohm,
Liono4ka [1.6K]

Answer:

I=1A

Explanation:

In parallel combination voltage is same

In R1

V=IR

V=2×4

V=8V

In R2

V=IR

I=V/R

I=8/8

I=1A

3 0
4 years ago
Is it possible for an object moving with a constant speed to accelerate? explain?
Andreas93 [3]
Yes, as long as it hasn't reached its maximum speed. Think of a car going 30mph, it can remain at this speed and travel at a constant rate; however, the car could also increase it's speed further. Hope this answers your question.
5 0
4 years ago
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