Answer:
The distance is 54.6 m
Explanation:
Given that,
Mass = 2.0 kg
Frictional coefficient = 0.21
Initial velocity = 15 m/s
We need to calculate the acceleration
Using formula of frictional force
We need to calculate the acceleration
We need to calculate the initial velocity
Using equation of motion
Put the value
Hence, The distance will be 54.6 m.
We have: Q = m.s.Δt
m = Q / s.Δt
Here, Q = 19.4 J
s = 6.28 J/g C
Δt = 22.9
Substitute their values into the expression:
m = 19.4 / 6.28×22.9
m = 19.4 / 143.81
m = 0.135 g
In short, Your Answer would be Option A
Hope this helps!
A peak = A Rms x Sq root 2
Therefore 3.6 x sq root of 2
A peak = 5.09
Answer:
B. South
Explanation:
An electric field can be defined as the amount of electric force per unit charge. The direction of the electric field can be determined by the motion of a positive test charge under the electric force.
The direction of electric field is radially outward for a positive charge and radially inward for a negative charge. Thus, for the electric field points toward SOUTH at a position directly south of a positive charge.
As you said p=w/t.
but, w=f×s
=500×5=2500j
t=10s
p=w/t
=2500/10=250 watts
