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3 years ago

If an astronaut has a mass of 112 kg, what is his weight on Earth where the acceleration due to gravity is 9.8m/s2?

Physics

1 answer:

coldgirl [10]3 years ago

3 0

Answer:

His weight on Earth is 1097.6N

Explanation:

You have to apply Newton's Second Law, F = m×a where F is force, m is mass and a is accerleration. Then, you have to substitute the following values into the equation :

$f = m \times a$

Let m = 112kg,

Let a = 9.8m/s²,

$f = 112 \times 9.8$

$f = 1097.6$

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storchak [24]

Answer:

a. 4.21 moles

b. 478.6 m/s

c. 1.5 times the root mean square velocity of the nitrogen gas outside the tank

Explanation:

Volume of container = 100.0 L

Temperature = 293 K

pressure = 1 atm = 1.01325 bar

number of moles n = ?

using the gas equation PV = nRT

n = PV/RT

R = 0.08206 L-atm- $mol^{-1}$ $K^{-1}$

Therefore,

n = (1.01325 x 100)/(0.08206 x 293)

n = 101.325/24.04 = 4.21 moles

The equation for root mean square velocity is

Vrms = $\sqrt{\frac{3RT}{M} }$

R = 8.314 J/mol-K

where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol

Vrms = $\sqrt{\frac{3*8.314*293}{0.0319} }$ = 478.6 m/s

For Nitrogen in thermal equilibrium with the oxygen, the root mean square velocity of the nitrogen will be proportional to the root mean square velocity of the oxygen by the relationship

$\frac{Voxy}{Vnit}$ = $\sqrt{\frac{Mnit}{Moxy} }$