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3 years ago

Are the 14 transition metals that follow lanthanum in the periodic table.

Chemistry

1 answer:

klio [65]3 years ago

3 0

Answer: Lanthanide or Lanthanides

Explanation: Sorry that I don’t have an explanation. I just answered the question correctly myself. <33

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Is volcanoes eruption rapid change or slow change

irakobra [83]

Answer:

Fast change

Explanation:

Weathering, erosion, and deposition are examples of slow change. Earthquakes, erupting volcanoes, and landslides happen fast. Therefore, they can change the Earth's surface very quickly.

3 0

2 years ago

How many moles of oxygen are present in 16 g of oxygen gas

makkiz [27]

Hope this helps

Answer- 1 mole

4 0

2 years ago

Read 2 more answers

20.00 g of aluminum (Al) reacts with 78.78 grams of molecular chlorine (Cl2), all of each reaction is completely consumed and as

shepuryov [24]

The reaction forms 98.76 g AlCl_3.

We have the masses of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.

M_r: ___26.98 _70.91 __133.34

________2Al + 3Cl_2 → 2AlCl_3

Mass/g: 20.00 _78.78

Step 2. Calculate the moles of each reactant

Moles of Al = 20.00 g Al × (1 mol Al /26.98 g Al) = 0.741 29 mol Al

Moles of Cl_2 = 78.78 g Cl_2 × (1 mol Cl_2 /70.91 g Cl_2) = 1.11 10 mol Cl_2

Step 3. Identify the limiting reactant

Calculate the moles of AlCl_3 we can obtain from each reactant.

From Al: Moles of AlCl_3 = 0.741 29 mol Al × (2 mol AlCl_3/2 mol Al) = 0.741 29 mol AlCl_3

From Cl_2: Moles of AlCl_3 = 1.11 10 mol Cl_2 × (2 mol AlCl_3/3 mol Cl_2) = 0.740 66 mol AlCl_3

Cl_2 is the limiting reactant because it gives the smaller amount of AlCl_3.

Step 4. Calculate the mass of AlCl_3.

Mass = 0.740 66 mol AlCl_3 × 133.34 g/1 mol AlCl_3 = 98.76 g AlCl_3

The reaction produces 98.76 g AlCl_3.

4 0

2 years ago

How much heat is given off when 869 g iron bar cools from 94 degrees celsius to 5

melomori [17]

Answer:

Heat given off was -34.34kJ

Explanation:

Mass of iron bar = 869g

Initial temperature (T1) = 94°C

Final temperature (T2) = 5°C

Specific heat capacity of iron (c) = 0.444J/g°C

Heat energy (Q) = Mc∇T

Q = heat energy

c = specific heat capacity

∇T = change in temperature

M = mass of the substance

Q = mc∇T

∇T = T2 - T1

Q = Mc(T2 -T1)

Q = 869 * 0.444 * (5 - 94)

Q = 385.836 * -89

Q = -34339.404J

Q = -34.34kJ

The heat given of was -34.34kJ

4 0

3 years ago

the following reaction gives a product with the molecular formula c4h8o2. draw the structure of the product.

grandymaker [24]

The following reaction gives a product with the molecular formula C₄H₈O₂. The diagram of the structure of the product can be seen in the image attached below.

The reaction between C₂H₂(ONa)₂ and C₂H₄Br results in the formation of the product C₄H₈O₂ and 2NaBr.

This reaction undergoes an SN₂ mechanism since there is no stable carbocation formed. In the reaction -O⁻Na⁺ attacks the ortho position in C₂H₄Br to form C₄H₈O₂.

In SN₂ mechanism is a nucleophilic substitution reaction where one bond is formed while another one is broken simultaneously.

The mechanism for the reaction can be seen in the image attached below.

Learn more about nucleophilic substitution reaction here:

brainly.com/question/4699407?referrer=searchResults

7 0

2 years ago