Answer:
Nitrate is considered SOLUBLE
Explanation:
please kindly refer to attachment for the step by step solution of the given problem.
Colloids and suspension are described as ________ heterogeneous _________ mixtures
1 answer:
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Answer:
a.
The molarity of Co³⁺ is 0.027 M
The molarity of Cl⁻ 0.081 M
b.
The molarity of Ni³⁺ is 0.022 M
The molarity of SO₄²⁻ is 0.033 M
c.
The molarity of Na⁺ is 0.031 M
The molarity of MnO₄⁻ is 0.031 M
d.
The molarity of Fe²⁺ is 0.021 M
The molarity of Br⁻ is 0.042 M
Explanation:
The molarity of each ion is the molarity of the salt times the number of ions in the formula. First, we will calculate the molarity of each salt.
<em>a. Cobalt(III) chloride . CoCl₃</em>
The molar mass of CoCl₃ is 165.29 g/mol. The molarity of CoCl₃ is:
The molarity of Co³⁺ is 1 × 0.027 M = 0.027 M
The molarity of Cl⁻ is 3 × 0.027 M = 0.081 M
<em>b. Nickel(III) sulfate . Ni₂(SO₄)₃</em>
The molar mass of Ni₂(SO₄)₃ is 405.57 g/mol. The molarity of Ni₂(SO₄)₃ is:
The molarity of Ni³⁺ is 2 × 0.011 M = 0.022 M
The molarity of SO₄²⁻ is 3 × 0.011 M = 0.033 M
<em>c. Sodium permanganate . NaMnO₄</em>
The molar mass of NaMnO₄ is 141.92 g/mol. The molarity of NaMnO₄ is:
The molarity of Na⁺ is 1 × 0.031 M = 0.031 M
The molarity of MnO₄⁻ is 1 × 0.031 M = 0.031 M
<em>d. Iron(II) bromide. FeBr₂</em>
The molar mass of FeBr₂ is 215.65 g/mol. The molarity of FeBr₂ is:
The molarity of Fe²⁺ is 1 × 0.021 M = 0.021 M
The molarity of Br⁻ is 2 × 0.021 M = 0.042 M