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Delicious77 [7]
3 years ago
7

Colloids and suspension are described as ________ heterogeneous _________ mixtures

Chemistry
1 answer:
solong [7]3 years ago
3 0

The question is already answered.

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Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3. Al2(SO4)3 + Ca(OH)2 Al(OH)3 + CaSO4
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Read 2 more answers
At 5000 K and 1.000 atm, 83.00% of the oxygen molecules in a sample have dissociated to atomic oxygen. At what pressure will 95.
Gala2k [10]

Answer:

At P_{total}  = 0.240\ atm; 95.0% of the molecules will dissociate at this temperature

Explanation:

The chemical  reaction of this dissociation is:

O_2 \leftrightarrow 2O_g

The ICE table is as follows:

                        O_2 \ \ \ \ \   \ \   \leftrightarrow \ \ \ \ \  \ \ \   2O_g

Initial               100                        0

Change            -83                      +166

Equilibrium          17                      166

The mole fractions of each  constituent is now calculated as:

Mole \ fraction \ of  \ O(X_o) = \frac{166}{183} = 0.9071

Mole \ fraction \ of  \ O_2(X_o_2_}}) = \frac{17}{183} = 0.0929

Given that the total pressure P_{total} = 1.000 atm ; the partial pressure of each gas is calculated by using Raoult's Law.

Partial \ Pressure \ of \  O (P_o) = X_oP_{total}\\\\ = 0.9071 \ atm

Partial \ Pressure \ of \  O_2 (P_o_2) = X_oP_{total}\\\\ = 0.0929 \ atm

Now; we proceed to determine the equilibrium constant K_c; which is illustrated as:

K_c = \frac{Po^2}{Po_2} \\ \\ K_c = \frac{(0.9072)^2}{0.0929} \\ \\ =8.86 \ atm

Let assume that the partial pressure of O_2 be x ;&

the change in pressure of  O_2 be y ; then

we can write that the following as the changes in concentration of species :

                          O_2 \ \ \ \ \   \ \   \leftrightarrow \ \ \ \ \  \ \ \   2O_g

Initial                    x                         0

Change              -y                          +2 y

Equilibrium         x - y                    2 y

From above; we can rewrite our equilibrium constant as:

K_c = \frac{(2y)^2}{x-y}  \\  \\ 8.86 = \frac{(2y)^2}{x-y}   ----- equation (1)

From the question; we are told that provided that 95% of the molecules dissociate at this temperature. Therefore, we have:

\frac{y}{x}*100 = 95%   -------- equation (2)

Solving and equating equation 1 and 2 ;

x = 0.123 atm

y = 0.117 atm

Thus, the pressure required can be calculated as :

P_{total} = (x-y) +2y \\ \\  P_{total} = (0.123- 0.117)+ 2(0.123) \\ \\ \\ P_{total}  = 0.240 \ atm

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3 years ago
Explain why ionic liquids are used in batteries?
Dovator [93]

Answer: onic solids are not dissociated in ions

Explanation:

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