Please help in test.

PLEASE HELP(will mark brainiest) Draw a quadrilateral A'B'C'D' that is a translation (x + 2, y - 4) of quadrilateral ABCD.

yuradex [85]

Answer:

New coordinates:

A: (2,-4)

B: (6,-4)

C: (7,1)

D: (3,1)

Step-by-step explanation:

You translate each of the starting coordinates by adding or subtracting them by the coordinates given.

x coordinates: 0+2=2 y coordinates: 0-4= -4

4+2=6 0-4= -4

5+2=7 5-4= 1

1+2=3 5-4= 1

7 0

3 years ago

Read 2 more answers

50 random teenagers were asked how many hours a day they use their phone. They spent an average of 7 hours a day with a standard

tatyana61 [14]

Answer:

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

Step-by-step explanation:

We have the standard deviation of the saple, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2\frac{1.3}{\sqrt{50}} = 0.4$

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

4 0

3 years ago

Omani wants to place a computer 24 1/2 inches long in the center of a table that is 28 3/4 inches wide. About how far from the e

kirza4 [7]

Answer:

2 1/8 inches from either edge

Step-by-step explanation:

First we have to subtract the computer length from the table length to find how much room there will be left on the table 28 3/4-24 2/4=4 1/4 and now since he wants it in the center we will divide that number by 2 because there will be some room on either side of the computer 4 1/4 divided by 2 is 2 1/8

I hope this helps and please don't hesitate to ask if there is anything still unclear!

7 0

3 years ago

A student was given the line y=2/3x-1 and the point (-7, 1/2) and asked to find an equation that went through the given point an

Colt1911 [192]

keeping in mind that perpendicular lines have <u>negative reciprocal</u> slopes, hmmm what's the slope of y=2/3x-1 anyway?

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{7em}y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x-1 \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so, notice, "one of his mistakes" is that he used 3/2 as the slope, not -3/2.

so, we're really looking for a line whose slope is -3/2 and runs through (-7, 1/2).

$\bf (\stackrel{x_1}{-7}~,~\stackrel{y_1}{\frac{1}{2}})~\hspace{10em} slope = m\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\cfrac{1}{2}=-\cfrac{3}{2}[x-(-7)]\implies y-\cfrac{1}{2}=-\cfrac{3}{2}(x+7) \\\\\\ y-\cfrac{1}{2}=-\cfrac{3}{2}x-\cfrac{21}{2}\implies y=-\cfrac{3}{2}x-\cfrac{21}{2}+\cfrac{1}{2}\implies y=-\cfrac{3}{2}x-10$

3 0

3 years ago

A rectangle is 12 m longer than it is wide. It’s perimeter is 68m. Find its length and width?

BabaBlast [244]

Answer:

Length: 23m

Width: 11

Step-by-step explanation:

68-24=44

44÷4=11

11+12=23

23+23=46+11=57+11=68

6 0

2 years ago