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Aleksandr-060686 [28]
3 years ago
12

Statement

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

Gg Buchanan vhcfyvhfty yogi vhcfyvhfty verifying

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Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4)?
Crazy boy [7]
Reflection that will produce an image with endpoints is y=-x
8 0
3 years ago
THE answer I need some help i do not get it
mamaluj [8]
Hi, AlaynaSanjurjo!
All we need to do is multiply 93 by 3, then divide it by 9. Since we have 3 boxes, and 93 tangerines in each box, we have to add them all up and divide them equally. I am sure you are capable of doing the equation now.
93 * 3 / 9

I hope I helped!

~Olivia

(P.S. I am working for Virtuoso and many don't consider giving others brainliest answers, but could you give me one? I need two more!)
6 0
3 years ago
If the reserve rate is 7% and a bank receives a deposit of $9000, how much of the $9000 is the bank free to lend?
elena55 [62]

7% Of 9000 is 630. Then subtract 630 from 9000. So your answer becomes 8370.

4 0
3 years ago
Read 2 more answers
An object is thrown upward at a speed of 96 feet per second by a machine from a height of 14 feet off the ground. The height of
liberstina [14]

Answer:

8t^2 -48 t -7=0

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

a= 8, b =-48, c = -7 and replacing we got:

t_1 = \frac{48 - \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = -0.1425

t_2 = \frac{48 + \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = 6.142

And since the time cannot be negative the correct answer for this cae would be t = 6.142 s

Step-by-step explanation:

If the question is: When will the object hit the ground at when the time is how many seconds?

We have the function for the heigth given by:

h(t) = -16t^2 +96 t +14

And we want to find the time where h(t) =0 so we can set like this the condition:

0 =-16t^2 +96 t +14

And we can rewrite the expression like this:

16t^2 -96 t -14 =0

We can divide both sides of the equation by 2 and we got:

8t^2 -48 t -7=0

And we can use the quadratic equation to solve for t like this:

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

a= 8, b =-48, c = -7 and replacing we got:

t_1 = \frac{48 - \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = -0.1425

t_2 = \frac{48 + \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = 6.142

And since the time cannot be negative the correct answer for this cae would be t = 6.142 s

7 0
3 years ago
Read 2 more answers
(?,3) is on the line y=2x+5.find the other half of the coordinate
kaheart [24]
Equation: y = 2x + 5

When y = 3, 

3 = 2x + 5
-5         -5 

-2  =  2x
÷2     ÷2

-1  = x 

x = -1 

------------------------------------------------------
Answer : The coordinate is (-1, 3) 
------------------------------------------------------

8 0
3 years ago
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