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3 years ago

Write the slope-intercept equation for a line that

Mathematics

1 answer:

Ber [7]3 years ago

3 0

9514 1404 393

Answer:

y = -1

Step-by-step explanation:

The slope formula tells you the slope is ...

m = (y2 -y1)/(x2 -x1)

m = (-1 -(-1))/(5 -3) = 0/2 = 0

We can find the y-intercept using the first point:

b = y -mx

b = -1 -0·3 = -1

Then the slope-intercept form is ...

y = mx + b

y = 0·x -1

y = -1 . . . . . simplified

_____

Of course, you can bypass all of that when you realize the two y-values are the same, so the line is a horizontal line with y equal to that value.

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Turning off the water while brushing your saves 379 centimetres of water .How many litres of water can you save if you turn off

Scrat [10]

First you need to find out how many cm of water that will be saved after brushing your teeth 3 times.

379 x 3 = 1137

Next you need the convert the cm to liters. You do this by dividing the cm total by 1000.

1137 / 1000 = 1.137

So you would save 1.137 liters of water while brushing your teeth 3 times.

Hope this helps!!

6 0

3 years ago

Read 2 more answers

List the following in order from least to greatest -3/5, -0.4, -1, -0.5

nikklg [1K]

-1

- 3/5

- 0.5

-0.4

The least is always the one furthest away from 0

5 0

4 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

3 years ago

The school talent show is 92 minutes long. Acts in the talent show are each about 4 minutes long. How many acts should there be?

valentina_108 [34]

Answer:

23 acts

Step-by-step explanation:

This is a division problem.

92/4 = 23

Answer: 23 acts

5 0

3 years ago

If anyone could help me, it would be greatly appreciated!

Sav [38]

Answer: $x=65^{\circ}, y=65^{\circ}, z=65^{\circ}$

Step-by-step explanation:

All radii of a circle are congruent, so by the base angles theorem

z = y = (180-50)/2 = 65.

Also, angles x and y are inscribed in the same arc, and they are thus congruent, meaning x = 65.

7 0

2 years ago